Math Problem Statement

Which of the following is logically equivalent to ~(A ∨ B)?

Solution

The question is asking to determine the logical equivalence of (AB)\sim (A \vee B) using the provided options. Let me solve it step by step:


Step 1: Apply De Morgan's Laws

The statement (AB)\sim (A \vee B) can be rewritten using De Morgan's Laws, which state: (AB)=(AB)\sim (A \vee B) = (\sim A \wedge \sim B)


Step 2: Compare to the Options

Now we examine the given options:

  • Option a: ABA \vee B
    This is simply the disjunction of AA and BB. Not equivalent.

  • Option b: AB\sim A \vee \sim B
    This is the negation of the conjunction (ABA \wedge B), but it does not match (AB)\sim (A \vee B). Not equivalent.

  • Option c: AB\sim A \wedge \sim B
    This matches (AB)\sim (A \vee B) exactly, based on De Morgan's Laws. Correct.

  • Option d: AB\sim A \wedge B
    This is a different conjunction and does not represent (AB)\sim (A \vee B). Not equivalent.


Final Answer:

Option c: AB\sim A \wedge \sim B is the correct choice.


Would you like a detailed explanation of De Morgan's Laws or help with another concept?

5 Related Questions:

  1. What are De Morgan's Laws and how are they applied in logic?
  2. How can logical equivalences simplify expressions?
  3. What is the difference between a conjunction (\wedge) and disjunction (\vee)?
  4. How would the equivalence change for (AB)\sim (A \wedge B)?
  5. Can you provide truth tables to confirm logical equivalence?

Tip:

Always use truth tables to verify logical equivalences if you're unsure about the results!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Logical Equivalence
De Morgan's Laws

Formulas

¬(A ∨ B) = (¬A ∧ ¬B)

Theorems

De Morgan's Laws

Suitable Grade Level

Undergraduate or High School (Grades 10-12)