Answer the following question
Which Boolean expression is equivalent to ¬ ( 𝐴 ∧ 𝐵 ) ¬(A∧B)?

Select your answer:
Select your answer
OPTION	ALTERNATIVE
A'

B'

A′∧B′

A′∨B′

None of the above

To determine which Boolean expression is equivalent to ¬(A ∧ B), we can use De Morgan's laws. De Morgan's laws state:

1. ¬(A ∧ B) = ¬A ∨ ¬B
2. ¬(A ∨ B) = ¬A ∧ ¬B

Applying the first law to ¬(A ∧ B):

¬(A ∧ B) = ¬A ∨ ¬B

Thus, the Boolean expression equivalent to ¬(A ∧ B) is A′ ∨ B′.

So the correct answer is:
**A′ ∨ B′**

Would you like any further details or have any questions? 

Here are some additional questions you might want to ask:
1. How do De Morgan's laws work?
2. Can you provide an example using De Morgan's laws?
3. What are some applications of De Morgan's laws in digital circuits?
4. How can I simplify a Boolean expression using Boolean algebra rules?
5. What is the difference between a conjunction and a disjunction in Boolean algebra?

**Tip:** When working with Boolean expressions, always remember to apply De Morgan's laws to simplify expressions involving negations.

Discover the equivalent Boolean expression to ¬(A ∧ B) using De Morgan's laws. Understand how ¬(A ∧ B) simplifies to A′ ∨ B′ and learn its application in Boolean algebra. Suitable for high school students and anyone interested in Boolean algebra concepts.

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