Math Problem Statement

solve exercice 3,4,5

solve exercice 3,4,5

Solution

Let us break down and solve Exercises 3, 4, and 5 from the assignment:


Exercise 03

Part (a): Design a combinatorial circuit that detects the parity of a 4-bit sequence A,B,C,DA, B, C, D

  • Parity Definition: Parity is even when the number of 1's is even, and odd when the number of 1's is odd.
  • Output PP: P=0P = 0 for even parity, P=1P = 1 for odd parity.

Solution: To compute parity:

  1. Use XOR gates since XOR outputs a high signal (1) when there is an odd number of 1's.
  2. Boolean equation: P=ABCDP = A \oplus B \oplus C \oplus D, where \oplus represents XOR.

Circuit Diagram:

  • Connect inputs A,B,C,DA, B, C, D to a chain of XOR gates:
    • First XOR: T1=ABT_1 = A \oplus B
    • Second XOR: T2=T1CT_2 = T_1 \oplus C
    • Final XOR: P=T2DP = T_2 \oplus D

Part (b): Implement using a 16×116 \times 1 MUX

To implement parity detection using a 16×116 \times 1 multiplexer:

  1. Treat A,B,C,DA, B, C, D as the 4 selection lines of the MUX.
  2. The MUX will have 1616 inputs corresponding to all possible combinations of A,B,C,DA, B, C, D.
  3. For each combination:
    • Set the MUX input to 1 if the combination has an odd number of 1's (parity = 1).
    • Otherwise, set the MUX input to 0.

Exercise 04

Part (a): Design a logic circuit for the 2's complement of a 3-bit binary number

  • Steps to Compute 2's Complement:
    1. Invert all bits of the number (1's complement).
    2. Add 11 to the least significant bit (LSB).

Circuit Description:

  1. Use NOT gates to invert all 3 bits (A,B,CA, B, C).
  2. Use a Half Adder or Full Adder to add 11 to the inverted bits.

Part (b): Use Half Adders

  • Use one Half Adder for the least significant bit addition:
    • C+1C' + 1
    • Carry from the LSB propagates to a Full Adder for B+CarryB' + \text{Carry}.
  • Repeat for the remaining bits.

Part (c): Use 8×18 \times 1 Multiplexer

  • Inputs: Original 3-bit number (A,B,CA, B, C).
  • Control: Use MUX inputs to define outputs based on 2's complement truth table.

Part (d): Use 1×81 \times 8 Demultiplexer

  • Invert the bits using NOT gates before connecting to Demux inputs.

Exercise 05

Boolean Function: X=AB+BC+ABCX = AB' + B'C + A'BC'

Part (a): Using a 3×83 \times 8 Decoder

  1. Use A,B,CA, B, C as inputs to the 3×83 \times 8 decoder.

  2. Enable decoder outputs corresponding to minterms of the function:

    • ABAB': Enable output 22 (010010).
    • BCB'C: Enable output 44 (100100).
    • ABCA'BC': Enable output 11 (001001).
  3. Combine outputs using OR gates.


Part (b): Using an 88-input Multiplexer

  1. Use A,B,CA, B, C as MUX select lines.
  2. Set MUX inputs I0,I1,...,I7I_0, I_1, ..., I_7 to match truth table values of XX.

Part (c): Using XOR Gate and 2:12:1 MUX

  1. Rearrange the function: X=(AB)C+ABCX = (A \oplus B) \cdot C + A'BC'.
  2. Implement ABA \oplus B with XOR, then combine with CC and ABCA'BC'.

Part (d): Using 4:14:1 MUX

  1. Use B,CB, C as MUX control inputs.
  2. Simplify terms and connect AA and constants to the MUX inputs.

Would you like to see the detailed steps or diagrams for any specific part? Here are some follow-up questions to consider:

  1. Do you need truth tables for any exercise?
  2. Should I detail the XOR implementation for parity detection?
  3. Would you like examples of simplifying Boolean expressions?
  4. Do you need a full diagram of the 16×116 \times 1 MUX implementation?
  5. Do you need help with Half Adder logic for the 2's complement?

Tip: For Boolean simplifications, always check for common terms to minimize gates!

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Math Problem Analysis

Mathematical Concepts

Logic circuits
Boolean algebra
Parity detection
2's complement
Combinational circuit design
Multiplexers and decoders

Formulas

Parity (XOR): P = A ⊕ B ⊕ C ⊕ D
2's Complement: Invert all bits + Add 1
Boolean Expression: X = AB' + B'C + A'BC'

Theorems

XOR gate properties
Half Adder and Full Adder principles
Truth table logic simplification

Suitable Grade Level

Undergraduate (First Year)