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### Problem 17:
**Given:**
- \( \log 2 = x \)
- \( \log 3 = y \)
  
Find the value of \( \log 0.45 \).

**Solution:**
We start by expressing 0.45 as a product of prime factors:
\[
0.45 = \frac{45}{100} = \frac{9 \times 5}{100} = \frac{3^2 \times 5}{2^2 \times 5^2}
\]
Thus, \( \log 0.45 = \log \left( \frac{9 \times 5}{100} \right) = \log (9) + \log(5) - \log(100) \).

This simplifies to:
```
log(0.45)->

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This page provides step-by-step solutions to problems involving logarithmic equations and inequalities. The problems use logarithmic properties such as the product and quotient rules. Suitable for students in Grades 9-12.

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