For this problem, let's first analyze it. You have an equation involving logarithms:

$\log_2 x - \log_2 3 = 4$

This can be solved by using logarithmic properties and applying similar methods. Here are ten similar problems that you might find helpful:

1. $\log_3 x - \log_3 5 = 2$
2. $\log_4 x - \log_4 2 = 3$
3. $\log_5 (x+1) - \log_5 4 = 1$
4. $\log_6 x - \log_6 9 = 2$
5. $\log_7 x - \log_7 8 = 3$
6. $\log_2 (x - 1) - \log_2 3 = 5$
7. $\log_3 (2x) - \log_3 4 = 1$
8. $\log_8 x - \log_8 5 = 2$
9. $\log_9 x - \log_9 2 = 4$
10. $\log_{10} x - \log_{10} 3 = 3$

Each of these problems uses a similar setup where the difference of two logarithms equals a constant, allowing you to apply the properties of logarithms to solve for $x$.

Would you like a detailed explanation on how to solve this type of problem?

Here are 5 follow-up questions you might consider:

1. How do you combine logarithmic expressions into a single logarithm?
2. How does changing the base of the logarithm affect the solution?
3. What is the general approach for solving logarithmic equations?
4. How do you handle logarithmic equations with variables in both terms?
5. What steps should you take when the equation has multiple logs with different bases?

Tip: Remember that $\log_b (a) - \log_b (c) = \log_b \left(\frac{a}{c}\right)$, a key property for solving these types of equations.