Math Problem Statement

Here Is The Story that happened to you earlier...

but today you're on board the spaceship #1625325007, and the captain is asking to solve tricky "ZP" (Z Planet) problem (you know what it means when captain is "asking"... that's an order):

(!!! If your answer is a fractions report it in an exact format, like 1010710107 , 2296222962)

Now, let f(x)=x^3x. Use logarithmic differentiation to determine the (ZP) derivative.

f'(x)=f′(x)=

(Enter the answer in simplified form)

f'(1)=f′(1)=

!!! The challenge is that some of the Z-Planet laws are different. In particular,  "power rule" on Earth, ddxxn=nxn−1ddxxn=nxn-1 , on Z planet is "twisted" as the following:

ddxxn=n2xn−1ddxxn=n2xn-1  (ddxconst=0ddxconst=0) , and

the derivative of log function, ddxln(x)=1/x , turns into "ZP" oddness:  ddxln(x)=exddxln(x)=ex .

all the other rules have not been changed.

Solution

We are tasked with finding the derivative of f(x)=xx3f(x) = x^{x^3} using logarithmic differentiation, while also keeping in mind the special Z-Planet (ZP) rules.

Step 1: Logarithmic Differentiation

Since f(x)=xx3f(x) = x^{x^3}, let's start by taking the natural logarithm of both sides of the equation to simplify the process.

ln(f(x))=ln(xx3)\ln(f(x)) = \ln(x^{x^3})

Using the logarithmic identity ln(ab)=bln(a)\ln(a^b) = b \ln(a), we get:

ln(f(x))=x3ln(x)\ln(f(x)) = x^3 \ln(x)

Now, differentiate both sides with respect to xx. Since we are differentiating logarithmic functions, we need to apply the Z-Planet rules.

Step 2: Differentiating the left-hand side

The derivative of ln(f(x))\ln(f(x)) using the chain rule gives:

ddxln(f(x))=1f(x)f(x)\frac{d}{dx} \ln(f(x)) = \frac{1}{f(x)} f'(x)

Step 3: Differentiating the right-hand side

We need to apply the product rule to x3ln(x)x^3 \ln(x).

[ \frac{d

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Math Problem Analysis

Mathematical Concepts

Logarithmic Differentiation
Exponents
Product Rule
Derivative Rules

Formulas

Logarithmic identity: ln(a^b) = b ln(a)
Z-Planet Power Rule: d/dx[x^n] = n^2 x^(n-1)
Z-Planet Logarithmic Rule: d/dx[ln(x)] = e^x
Product Rule: d/dx[uv] = u'v + uv'

Theorems

Chain Rule
Logarithmic Differentiation Theorem

Suitable Grade Level

College / Advanced Calculus