Math Problem Statement

1. If told that log 3 = 0.477, which of the following statements is correct? 2. If f(x) = (3x + 2)/5, then f⁻¹(x) = ?

Solution

Let’s analyze and solve the two questions in your uploaded image.


Question 7:

Given: log 3 = 0.477
Find the correct statement about log 81.

Solution:

We know: 81=3481 = 3^4 Using the logarithmic property: log(34)=4log(3)\log(3^4) = 4 \cdot \log(3) Substituting log(3)=0.477\log(3) = 0.477: log(81)=40.477=1.908\log(81) = 4 \cdot 0.477 = 1.908

Checking Options:

  • (a) log81=0.477×0.477×0.477×0.477\log 81 = 0.477 \times 0.477 \times 0.477 \times 0.477: Incorrect, since log\log does not behave this way.
  • (b) log81=4(0.477)\log 81 = 4(0.477): Correct, as shown in the solution above.
  • (c) None of the options: Incorrect.
  • (d) log81=3(0.477)\log 81 = 3(0.477): Incorrect.

Answer: (b)


Question 8:

Given: f(x)=3x+25f(x) = \frac{3x + 2}{5}
Find the inverse, f1(x)f^{-1}(x).

Solution:

To find the inverse, solve for xx in terms of yy:

  1. Let y=f(x)=3x+25y = f(x) = \frac{3x + 2}{5}. y=3x+25y = \frac{3x + 2}{5}
  2. Multiply through by 5: 5y=3x+25y = 3x + 2
  3. Rearrange to solve for xx: 3x=5y23x = 5y - 2 x=5y23x = \frac{5y - 2}{3} Thus, the inverse function is: f1(x)=5x23f^{-1}(x) = \frac{5x - 2}{3}

Checking Options:

  • (a) (35x)/2(3 - 5x)/2: Incorrect.
  • (b) None of the options: Incorrect.
  • (c) (5x2)/3(5x - 2)/3: Correct, as derived.
  • (d) (5x+2)/3(5x + 2)/3: Incorrect.

Answer: (c)


Do you want me to elaborate on any step or property used in solving these questions?


Relative Questions:

  1. What are the key logarithmic properties used in such problems?
  2. How do you derive the inverse of a linear function in general?
  3. Why is log(34)\log(3^4) simplified to 4log(3)4 \cdot \log(3)?
  4. Can you explain the difference between direct and inverse functions?
  5. How can you verify an inverse function is correct?

Tip:

Always check your calculations by substituting the inverse back into the original function!

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Math Problem Analysis

Mathematical Concepts

Logarithmic properties
Inverse functions

Formulas

log(a^b) = b × log(a)
Inverse function calculation: Swap x and y and solve for the new y

Theorems

Logarithmic properties
Inverse of linear functions

Suitable Grade Level

Grades 9-12