Math Problem Statement

Define a linear transformation T: P_2 → ℝ² by T(p) = [p(0), p(0)]'. Find polynomials p₁ and p₂ in P_2 that span the kernel of T, and describe the range of T.

Solution

We are given a linear transformation T:P2R2T : \mathbb{P}_2 \to \mathbb{R}^2 defined by

T(p)=[p(0)p(0)]T(p) = \begin{bmatrix} p(0) \\ p(0) \end{bmatrix}

where P2\mathbb{P}_2 is the space of polynomials of degree at most 2.

Step 1: Kernel of TT

The kernel of TT, denoted ker(T)\ker(T), is the set of polynomials p(x)P2p(x) \in \mathbb{P}_2 such that T(p)=0T(p) = \mathbf{0}. In other words, we want to find polynomials p(x)P2p(x) \in \mathbb{P}_2 such that:

T(p)=[p(0)p(0)]=[00].T(p) = \begin{bmatrix} p(0) \\ p(0) \end{bmatrix} = \begin{bmatrix} 0 \\ 0 \end{bmatrix}.

This implies that:

p(0)=0.p(0) = 0.

Thus, the polynomials in the kernel of TT must satisfy p(0)=0p(0) = 0. Any polynomial in P2\mathbb{P}_2 can be written as:

p(x)=a2x2+a1x+a0.p(x) = a_2 x^2 + a_1 x + a_0.

For p(0)=0p(0) = 0, we require:

a0=0.a_0 = 0.

Therefore, the polynomials in the kernel of TT are of the form:

p(x)=a2x2+a1x.p(x) = a_2 x^2 + a_1 x.

The set of polynomials that span the kernel are:

p1(x)=xandp2(x)=x2.p_1(x) = x \quad \text{and} \quad p_2(x) = x^2.

So, the kernel of TT is spanned by {x,x2}\{x, x^2\}.

Step 2: Range of TT

The range of TT, denoted range(T)\text{range}(T), is the set of all possible outputs of TT. Since T(p)=[p(0)p(0)]T(p) = \begin{bmatrix} p(0) \\ p(0) \end{bmatrix}, the output is always of the form:

[cc]\begin{bmatrix} c \\ c \end{bmatrix}

where c=p(0)c = p(0). Therefore, the range of TT consists of all vectors in R2\mathbb{R}^2 where both components are equal. This is the subspace of R2\mathbb{R}^2 spanned by the vector:

[11].\begin{bmatrix} 1 \\ 1 \end{bmatrix}.

Thus, the range of TT is the 1-dimensional subspace of R2\mathbb{R}^2 spanned by [11]\begin{bmatrix} 1 \\ 1 \end{bmatrix}.

Conclusion:

  • The kernel of TT is spanned by {x,x2}\{x, x^2\}.
  • The range of TT is the subspace of R2\mathbb{R}^2 spanned by [11]\begin{bmatrix} 1 \\ 1 \end{bmatrix}.

Would you like further details or have any other questions?

Follow-up questions:

  1. How is the dimension of the kernel related to the dimension of the polynomial space P2\mathbb{P}_2?
  2. What is the rank-nullity theorem, and how can it be applied to this linear transformation?
  3. Can you describe the geometric interpretation of the range and kernel in this context?
  4. What would change if T(p)T(p) was defined differently, such as T(p)=[p(1)p(1)]T(p) = \begin{bmatrix} p(1) \\ p(-1) \end{bmatrix}?
  5. How would you verify that {x,x2}\{x, x^2\} spans the kernel of TT?

Tip:

To check if a set of polynomials spans a subspace, ensure that they are linearly independent and that any element of the subspace can be written as a linear combination of the set.

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Math Problem Analysis

Mathematical Concepts

Linear Transformations
Polynomial Spaces
Kernel
Range

Formulas

T(p) = [p(0), p(0)]
p(x) = a₂x² + a₁x + a₀

Theorems

Rank-Nullity Theorem

Suitable Grade Level

Undergraduate Mathematics