Math Problem Statement

Find the kernel, image, nullity, and rank of the transformation T(x, y, z) = (x+z, y+z) and verify Sylvester's Law. Also, find T(1,1) given T(1,0) = (3,-1,5) and T(0,1) = (3,1,-1).

Solution

Let’s analyze and solve the given mathematical problems step by step.

1. Task 1: Linear Transformation T:R2R3T: \mathbb{R}^2 \to \mathbb{R}^3

  • Given data:

    • T(1,0)=(3,1,5)T(1,0) = (3,-1,5)
    • T(0,1)=(3,1,1)T(0,1) = (3,1,-1)

    We are tasked with finding T(1,1)T(1,1).

Solution:

By the linearity of TT, we can write: T(1,1)=T(1,0)+T(0,1)T(1,1) = T(1,0) + T(0,1) Substitute: T(1,1)=(3,1,5)+(3,1,1)T(1,1) = (3,-1,5) + (3,1,-1) Perform component-wise addition: T(1,1)=(6,0,4)T(1,1) = (6,0,4)


2. Task 2: Linear Transformation T:R3R2T: \mathbb{R}^3 \to \mathbb{R}^2

  • Given transformation:
    T(x,y,z)=(x+z,y+z)T(x,y,z) = (x + z, y + z)
  • Tasks:
    • Find the kernel, image, nullity, and rank of TT.

Solution:

  • Kernel:
    The kernel is the set of vectors (x,y,z)R3(x, y, z) \in \mathbb{R}^3 such that T(x,y,z)=(0,0)T(x,y,z) = (0,0).
    Solve: x+z=0andy+z=0x + z = 0 \quad \text{and} \quad y + z = 0 From the first equation, z=xz = -x.
    From the second equation, z=yz = -y.
    Therefore, x=yx = y, and the kernel is: Ker(T)=span{(1,1,1)}\text{Ker}(T) = \text{span}\{(1,1,-1)\}

  • Image:
    The image of TT is all possible outputs (x+z,y+z)(x+z, y+z). By varying x,y,zx, y, z, we see the image is all of R2\mathbb{R}^2: Im(T)=R2\text{Im}(T) = \mathbb{R}^2

  • Nullity:
    The nullity is the dimension of the kernel, which is 1 (since the kernel is spanned by one vector).

  • Rank:
    The rank is the dimension of the image, which is 2 (since the image is R2\mathbb{R}^2).

  • Verify Sylvester's Law:
    Using the rank-nullity theorem: Rank+Nullity=Dimension of domain\text{Rank} + \text{Nullity} = \text{Dimension of domain} Here: 2+1=32 + 1 = 3 Verified.


3. Task 3: Verify Linearity for T:V2V2T: V_2 \to V_2, T(x,y)=(x+y,x+2)T(x,y) = (x+y, x+2):

  • Check additivity:
    Let u=(x1,y1)u = (x_1, y_1), v=(x2,y2)v = (x_2, y_2).
    Check: T(u+v)=T((x1+x2,y1+y2))=((x1+x2)+(y1+y2),(x1+x2)+2)T(u + v) = T((x_1 + x_2, y_1 + y_2)) = ((x_1+x_2)+(y_1+y_2), (x_1+x_2)+2) On the other hand: T(u)+T(v)=(x1+y1,x1+2)+(x2+y2,x2+2)T(u) + T(v) = (x_1+y_1, x_1+2) + (x_2+y_2, x_2+2) Both simplify to: ((x1+x2)+(y1+y2),(x1+x2)+2)((x_1+x_2)+(y_1+y_2), (x_1+x_2)+2) Hence, additivity is satisfied.

  • Check homogeneity:
    Let cc be a scalar. Check: T(cu)=T(c(x1,y1))=T((cx1,cy1))=(cx1+cy1,cx1+2)T(cu) = T(c(x_1, y_1)) = T((cx_1, cy_1)) = (cx_1+cy_1, cx_1+2) On the other hand: cT(u)=c(x1+y1,x1+2)=(cx1+cy1,cx1+2)cT(u) = c(x_1+y_1, x_1+2) = (cx_1+cy_1, cx_1+2) Homogeneity is satisfied.

Thus, TT is linear.


Do you want further details on any of the steps? Here are some related questions:

  1. How to compute the matrix representation of linear transformations?
  2. What is the geometric meaning of the kernel and image of a transformation?
  3. How to use rank-nullity theorem in higher dimensions?
  4. Can a transformation have both full rank and a non-trivial kernel?
  5. What is the practical significance of verifying Sylvester's law?

Tip: Always verify both kernel and image spaces when analyzing linear transformations to ensure consistency

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Math Problem Analysis

Mathematical Concepts

Linear Transformations
Kernel and Image of a Linear Transformation
Rank-Nullity Theorem
Sylvester's Law

Formulas

T(x, y, z) = (x+z, y+z)
Rank + Nullity = Dimension of the Domain

Theorems

Rank-Nullity Theorem
Sylvester's Law

Suitable Grade Level

Undergraduate Linear Algebra