Math Problem Statement

Find the values for a and b that satisfy both of the following equations. Add the values found together to get one number: 3a + 4b = 11, b = 2a

Solution

To solve this problem, we need to find the values of aa and bb that satisfy both given equations:

  1. 3a+4b=113a + 4b = 11
  2. b=2ab = 2a

Step 1: Substitute b=2ab = 2a into the first equation.

Replace bb in the first equation with 2a2a:

3a+4(2a)=113a + 4(2a) = 11

3a+8a=113a + 8a = 11

11a=1111a = 11

Step 2: Solve for aa.

Divide both sides by 11:

a=1a = 1

Step 3: Find bb using b=2ab = 2a.

Substitute a=1a = 1 into b=2ab = 2a:

b=2(1)=2b = 2(1) = 2

Step 4: Add the values of aa and bb together.

a+b=1+2=3a + b = 1 + 2 = 3

The correct answer is A. 3.

Do you want more details or have any questions? Here are some related questions you might consider:

  1. How can you solve systems of equations using substitution?
  2. What other methods exist for solving systems of linear equations?
  3. Can you solve systems with more than two variables?
  4. What are the conditions for a system of equations to have a unique solution?
  5. How does graphing help in visualizing the solutions of linear equations?

Tip: Always check your solutions by substituting them back into the original equations to ensure they satisfy both equations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Substitution Method

Formulas

3a + 4b = 11
b = 2a

Theorems

Substitution method for solving systems of equations

Suitable Grade Level

Grades 7-9