Math Problem Statement

Use the two equations below to solve for a and b. 18 = 2a + 10 3a = b + 2

Solution

To solve the given system of equations for aa and bb, let's go through the solution step by step:

Given Equations:

  1. 18=2a+1018 = 2a + 10
  2. 3a=b+23a = b + 2

Step 1: Solve for aa

From the first equation: 18=2a+1018 = 2a + 10

Subtract 10 from both sides: 8=2a8 = 2a

Divide by 2: a=4a = 4

Step 2: Solve for bb

Substitute a=4a = 4 into the second equation: 3(4)=b+23(4) = b + 2

Simplify: 12=b+212 = b + 2

Subtract 2 from both sides: b=10b = 10

Final Solution:

a=4,b=10a = 4, \, b = 10

Would you like a detailed explanation of any step? Here are some related questions:

  1. How do you solve systems of equations using substitution?
  2. What other methods can solve a system of linear equations?
  3. Can these equations be graphed to verify the solution?
  4. How do you check the solution of a system of equations?
  5. What is the elimination method for solving equations?

Tip: Always check your solution by substituting back into the original equations to ensure it satisfies both!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Substitution Method

Formulas

Linear equation formula y = mx + b

Theorems

Substitution method

Suitable Grade Level

Grades 7-9