Math Problem Statement

The sales of a small company were ​$46,000 in its third year of operation and ​$88,000 in its sixth year. Let y represent sales in the xth year of operation. Assume that the data can be approximated by a straight line. ​(a) Find the slope of the sales​ line, and give an equation for the line in the form y equals mx plus b. ​(b) Use your answer from part​ (b) to find out how many years must pass before the sales surpass ​$110 comma 000.

Solution

We are given that the sales of a small company were $46,000 in its third year of operation (i.e., when x=3x = 3) and $88,000 in its sixth year of operation (i.e., when x=6x = 6). We are asked to:

  1. Find the slope of the sales line and give an equation for the line in the form y=mx+by = mx + b.
  2. Use the equation to find how many years must pass before the sales surpass $110,000.

Part (a): Find the slope and equation of the line.

We have two points on the line:

  • (x1,y1)=(3,46,000)(x_1, y_1) = (3, 46,000)
  • (x2,y2)=(6,88,000)(x_2, y_2) = (6, 88,000)

Step 1: Find the slope.

The formula for the slope mm of a line through two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is: m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}

Substituting the values: m=88,00046,00063=42,0003=14,000m = \frac{88,000 - 46,000}{6 - 3} = \frac{42,000}{3} = 14,000 So, the slope is m=14,000m = 14,000.

Step 2: Find the equation of the line.

The general form of a line is: y=mx+by = mx + b We already know m=14,000m = 14,000. Now, we need to find bb, the y-intercept. To do this, substitute one of the given points (let's use (3,46,000)(3, 46,000)) into the equation:

46,000=14,000(3)+b46,000 = 14,000(3) + b 46,000=42,000+b46,000 = 42,000 + b b=46,00042,000=4,000b = 46,000 - 42,000 = 4,000

Thus, the equation of the sales line is: y=14,000x+4,000y = 14,000x + 4,000

Part (b): Find how many years must pass before the sales surpass $110,000.

We need to find the value of xx such that y=110,000y = 110,000.

Using the equation y=14,000x+4,000y = 14,000x + 4,000, set y=110,000y = 110,000 and solve for xx:

110,000=14,000x+4,000110,000 = 14,000x + 4,000 110,0004,000=14,000x110,000 - 4,000 = 14,000x 106,000=14,000x106,000 = 14,000x x=106,00014,000=7.57x = \frac{106,000}{14,000} = 7.57

Thus, the sales will surpass $110,000 after approximately 7.57 years. Since we can't have a fraction of a year in this context, we round up to the next whole year, meaning the sales will surpass $110,000 after 8 years.

Final Answers:

  • (a) The slope of the sales line is 14,000, and the equation is y=14,000x+4,000y = 14,000x + 4,000.
  • (b) The sales will surpass $110,000 after 8 years.

Would you like further details or clarifications on any part?

Here are some related questions to consider:

  1. What would the sales be in the 10th year using the same equation?
  2. How many years would it take for sales to reach $150,000?
  3. What does the slope of the line represent in the context of this problem?
  4. How would the equation change if sales in the first year were $20,000?
  5. Can we estimate the company’s sales growth if a quadratic function better represented the data?

Tip: When interpreting a linear equation, the slope represents the rate of change, while the intercept represents the starting point or initial value.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Linear Equations
Slope-Intercept Form

Formulas

Slope formula: m = (y2 - y1) / (x2 - x1)
Equation of a line: y = mx + b

Theorems

Slope-Intercept Theorem

Suitable Grade Level

Grades 9-10