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The correct answer is **A) 9.3 grams**.

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Here are five related questions:
1. How do you calculate the rate of change in a linear relationship?
2. If the larva's growth was exponential instead of linear, how would the solution differ?
3. How would you model the growth of the larva using a function?
4. How does the time interval affect the rate of growth in linear functions?
5. Can you solve a similar problem if the initial and final masses were different?

**Tip**: In linear growth problems, finding the rate of change per unit time is key to predicting future values accurately.

The mass of an insect larva increased over a 48-hour period. At the beginning of the period, the mass of the larva was 8.0 grams, and at the end of the period, the mass was 12 grams. If the increase in the mass was linear, what was the mass of the larva 6 hours after its mass was 9.0 grams?

Explore the linear growth of an insect larva's mass, increasing from 8.0 grams to 12.0 grams over 48 hours. Calculate the larva's mass 6 hours after it reached 9.0 grams using linear growth principles. This problem covers concepts such as rate of change and linear equations, suitable for students in Grades 6-8.

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