Let's solve these equations one by one.

1. $3(x + 5) = 39$

Distribute the $3$ across the terms inside the parentheses: $3x + 15 = 39$ Subtract $15$ from both sides: $3x = 24$ Divide both sides by $3$: $x = 8$

2. $4x - 9 = x + 3$

Subtract $x$ from both sides to bring all $x$-terms to one side: $3x - 9 = 3$ Add $9$ to both sides: $3x = 12$ Divide both sides by $3$: $x = 4$

3. $2(2x + 7) = -6$

Distribute the $2$ across the terms inside the parentheses: $4x + 14 = -6$ Subtract $14$ from both sides: $4x = -20$ Divide both sides by $4$: $x = -5$

4. $3(x + 5) = 2(x - 1)$

Distribute both sides: $3x + 15 = 2x - 2$ Subtract $2x$ from both sides: $x + 15 = -2$ Subtract $15$ from both sides: $x = -17$

Final Results:

1. $x = 8$
2. $x = 4$
3. $x = -5$
4. $x = -17$

Would you like further explanation on any step or more practice questions?

Related Questions:

1. Can you solve $5(x - 3) = 20$?
2. What happens if you multiply both sides of an equation by zero?
3. How do you check the solution of an equation?
4. Solve $2x + 3 = 4x - 7$.
5. What is the difference between solving a linear equation and a quadratic equation?

Tip:

Always simplify the equation step-by-step to avoid errors. Rewrite the equation after every operation for clarity!