Math Problem Statement

Find the solutions for questions 14 to 18 on linear equations and slopes.

Solution

Let's go through the questions in the image step-by-step to find the answers.


Question 14

Equation of a line passing through points (-2, 4) and (6, 3).

  1. First, calculate the slope mm: m=y2y1x2x1=346(2)=18=18m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 4}{6 - (-2)} = \frac{-1}{8} = -\frac{1}{8}

  2. Use the point-slope form yy1=m(xx1)y - y_1 = m(x - x_1) with point (2,4)(-2, 4): y4=18(x+2)y - 4 = -\frac{1}{8}(x + 2)

  3. Expanding and simplifying: y4=18x14y - 4 = -\frac{1}{8}x - \frac{1}{4} 8y32=x28y - 32 = -x - 2 x+8y30=0x + 8y - 30 = 0 Answer: A. x+8y30=0x + 8y - 30 = 0


Question 15

Gradient of the line with equation 4x+y=54x + y = 5.

  1. Rewrite in slope-intercept form y=mx+by = mx + b: y=4x+5y = -4x + 5 The gradient (slope) m=4m = -4.

    Answer: C. Gradient = -4


Question 16

Equation of a line passing through (0, -5) and parallel to 4x+2y8=04x + 2y - 8 = 0.

  1. Rewrite 4x+2y8=04x + 2y - 8 = 0 in slope-intercept form: 2y=4x+82y = -4x + 8 y=2x+4y = -2x + 4 Since parallel lines have the same slope, the slope of the new line is also 2-2.

  2. Using point-slope form with point (0,5)(0, -5): y+5=2(x0)y + 5 = -2(x - 0) y=2x5y = -2x - 5

    Answer: B. y=2x5y = -2x - 5


Question 17

Equation of a line passing through (8, -4) and parallel to 3x+y6=03x + y - 6 = 0.

  1. Rewrite 3x+y6=03x + y - 6 = 0 in slope-intercept form: y=3x+6y = -3x + 6 So, the slope of the new line is also 3-3.

  2. Using point-slope form with point (8,4)(8, -4): y+4=3(x8)y + 4 = -3(x - 8) y=3x+244y = -3x + 24 - 4 y=3x+20y = -3x + 20 Converting this to standard form: 3x+y20=03x + y - 20 = 0

    Answer: B. 3x+y20=03x + y - 20 = 0


Question 18

Equation of a line passing through (3, 4) and parallel to the line passing through points A(2,6)A(-2, -6) and B(8,14)B(8, 14).

  1. First, find the slope of the line through points AA and BB: m=14(6)8(2)=2010=2m = \frac{14 - (-6)}{8 - (-2)} = \frac{20}{10} = 2

  2. Use point-slope form with point (3,4)(3, 4): y4=2(x3)y - 4 = 2(x - 3) y=2x6+4y = 2x - 6 + 4 y=2x2y = 2x - 2 Converting to standard form: 2xy2=02x - y - 2 = 0

    Answer: C. 2xy2=02x - y - 2 = 0


Would you like more details or have any questions?


Related Questions

  1. How do you find the equation of a line passing through two points?
  2. What is the point-slope form of a line, and how is it useful?
  3. How can you determine if two lines are parallel?
  4. How do you convert from slope-intercept form to standard form?
  5. What are the key differences between slope-intercept form and standard form of a line?

Tip: When finding equations of parallel lines, remember that parallel lines have identical slopes.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Coordinate Geometry
Slopes of Lines
Parallel Lines

Formulas

Slope formula: m = (y2 - y1) / (x2 - x1)
Point-slope form: y - y1 = m(x - x1)
Slope-intercept form: y = mx + b
Standard form of a line: Ax + By + C = 0

Theorems

Lines with identical slopes are parallel.

Suitable Grade Level

Grades 10-12