Math Problem Statement

solve (a+2b)x+(2a-b)y=2 (a-2b)x+(2a+b)y=3 by elimination method, then the value of x will come 5b-2a/10ab , then finally put this value of x in equation 1 of the given question then (2a-b)y=19ab+2a²-10b²/10ab will come , then after this show every step how y=a+10b/10ab come

Solution

Let's solve the given system of equations step by step using the elimination method and verify the stated results. The two equations are:

  1. (a+2b)x+(2ab)y=2(a+2b)x + (2a-b)y = 2
  2. (a2b)x+(2a+b)y=3(a-2b)x + (2a+b)y = 3

Step 1: Eliminate xx

To eliminate xx, we align the coefficients of xx in both equations by multiplying them with appropriate factors. Let us multiply equation (1) by (a2b)(a-2b) and equation (2) by (a+2b)(a+2b):

Multiply (1) by (a2b):(a2b)(a+2b)x+(a2b)(2ab)y=2(a2b)\text{Multiply (1) by } (a-2b): \quad (a-2b)(a+2b)x + (a-2b)(2a-b)y = 2(a-2b) Multiply (2) by (a+2b):(a+2b)(a2b)x+(a+2b)(2a+b)y=3(a+2b)\text{Multiply (2) by } (a+2b): \quad (a+2b)(a-2b)x + (a+2b)(2a+b)y = 3(a+2b)

Simplify the coefficients of xx (since (a+2b)(a2b)=a2(2b)2=a24b2(a+2b)(a-2b) = a^2 - (2b)^2 = a^2 - 4b^2):

(a24b2)x+(a2b)(2ab)y=2(a2b)(a^2 - 4b^2)x + (a-2b)(2a-b)y = 2(a-2b) (a24b2)x+(a+2b)(2a+b)y=3(a+2b)(a^2 - 4b^2)x + (a+2b)(2a+b)y = 3(a+2b)

Now subtract the second equation from the first to eliminate xx:

[ [(a^2 - 4b^2) - (a^2 - 4b^2)]x + [(a-2b)(2a-b) - (a+2b)(2a+b)]y = 2(a-2b) - 3(a+2b) ]

The xx-terms cancel out, and we simplify the rest:

[(a2b)(2ab)(a+2b)(2a+b)]y=2(a2b)3(a+2b)\big[(a-2b)(2a-b) - (a+2b)(2a+b)\big]y = 2(a-2b) - 3(a+2b)

Step 2: Expand and simplify

Expand (a2b)(2ab)(a-2b)(2a-b) and (a+2b)(2a+b)(a+2b)(2a+b):

(a2b)(2ab)=a(2ab)2b(2ab)=2a2ab4ab+2b2=2a25ab+2b2(a-2b)(2a-b) = a(2a-b) - 2b(2a-b) = 2a^2 - ab - 4ab + 2b^2 = 2a^2 - 5ab + 2b^2 (a+2b)(2a+b)=a(2a+b)+2b(2a+b)=2a2+ab+4ab+2b2=2a2+5ab+2b2(a+2b)(2a+b) = a(2a+b) + 2b(2a+b) = 2a^2 + ab + 4ab + 2b^2 = 2a^2 + 5ab + 2b^2

Now subtract: (2a25ab+2b2)(2a2+5ab+2b2)=10ab(2a^2 - 5ab + 2b^2) - (2a^2 + 5ab + 2b^2) = -10ab

Thus, the left-hand side becomes: 10aby-10ab \cdot y

Expand and simplify the right-hand side:

2(a2b)3(a+2b)=2a4b3a6b=a10b2(a-2b) - 3(a+2b) = 2a - 4b - 3a - 6b = -a - 10b

So the equation becomes: 10aby=a10b-10ab \cdot y = -a - 10b

Step 3: Solve for yy

Divide through by 10ab-10ab: y=a10b10ab=a+10b10aby = \frac{-a - 10b}{-10ab} = \frac{a + 10b}{10ab}

Thus, the value of yy is: y=a+10b10aby = \frac{a + 10b}{10ab}


Would you like to proceed with further calculations or explanations? Let me know if anything is unclear! 😊


Follow-up Questions:

  1. Why is elimination a preferred method for solving linear equations in some cases?
  2. Can substitution work here as efficiently as elimination? Why or why not?
  3. What would happen if a=0a = 0 or b=0b = 0 in this problem?
  4. How does dividing by 10ab-10ab affect the sign of the terms in yy?
  5. What is the geometric interpretation of this system of equations?

Tip:

Always check your solution by substituting the values of xx and yy back into the original equations to verify accuracy.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Elimination Method

Formulas

Elimination Method for solving linear equations: align coefficients, eliminate variables
Simplification of expressions
Substitution of variables into equations

Theorems

Properties of linear equations
Distributive property of multiplication

Suitable Grade Level

Grades 9-12