To solve this activity, we need to complete the tables by substituting the values of $x$ into each equation to find $y$, then use the code key to determine the corresponding letter for each circled number. Let's work through the questions systematically.

I'll compute the answers for the first equation and show the process.

Equation 1: $y = -2x$

• For $x = 1$, $y = -2(1) = -2$ ⟹ circled number: 2 ⟹ Code key: $R$.
• For $x = 4$, $y = -2(4) = -8$.
• For $x = -5$, $y = -2(-5) = 10$.
• For $x = 3$, $y = -2(3) = -6$.

I'll calculate all rows, then fill in the code based on the circled numbers. Let me process this systematically for the entire sheet.import pandas as pd

Equations and x-values for each table

data = { 1: {'equation': lambda x: -2 * x, 'x_values': [1, 4, -5, 3]}, 2: {'equation': lambda x: 4 + 2 * x, 'x_values': [3, -7, 1, -3]}, 3: {'equation': lambda x: -3 * x + 1, 'x_values': [3, 6, 4, -2]}, 4: {'equation': lambda x: 0.5 * x - 4, 'x_values': [10, -2, 8, -8]}, 5: {'equation': lambda x: -x + 6, 'x_values': [4, -1, 6, 0]}, 6: {'equation': lambda x: (-3 / 2) * x - 2, 'x_values': [4, 2, 0, -2]}, 7: {'equation': lambda x: 7 - 3 * x, 'x_values': [6, 1, 0, -2]}, 8: {'equation': lambda x: 1 - x, 'x_values': [-2, -9, 9, 0]} }

Solve equations for all tables

results = {} for table_num, details in data.items(): equation = details['equation'] x