Let's solve this problem step by step. The given equation is:

$y = -2x$

1. Finding the y-intercept:

The y-intercept occurs when $x = 0$. Substituting $x = 0$ into the equation:

$y = -2(0) = 0$

Thus, the y-intercept is $(0, 0)$.

2. Finding the x-intercept:

The x-intercept occurs when $y = 0$. Substituting $y = 0$ into the equation:

$0 = -2x$

Solving for $x$:

$x = 0$

Thus, the x-intercept is $(0, 0)$.

Conclusion:

Both the x-intercept and y-intercept are $(0, 0)$. So, you can fill in the boxes as follows:

• The x-intercept is $(0, 0)$.
• The y-intercept is $(0, 0)$.

Would you like more details or have any questions?

Here are some related questions to explore:

1. What are the x- and y-intercepts of the line $y = 3x + 5$?
2. How do you find intercepts for quadratic equations?
3. Can a line have no x-intercept or y-intercept?
4. What does the slope of a line represent?
5. How do intercepts relate to graphing linear functions?

Tip: The x- and y-intercepts are useful for quickly sketching the graph of a line without needing multiple points!