The given equation is:

$x - 2y - 4 = 0$

We can rearrange this equation to solve for $y$ in terms of $x$.

Step-by-step solution:

1. Add 4 to both sides:

$x - 2y = 4$

2. Subtract $x$ from both sides:

$-2y = -x + 4$

3. Divide both sides by $-2$:

$y = \frac{-x + 4}{-2}$

Simplifying this:

$y = \frac{x}{2} - 2$

So, the equation of the line in slope-intercept form is:

$y = \frac{1}{2}x - 2$

This represents a straight line with a slope of $\frac{1}{2}$ and a y-intercept of $-2$.

Would you like more details on how to graph this, or any further explanation?

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Here are 5 related questions you might be interested in:

1. How do you find the slope of a line from an equation?
2. What is the slope-intercept form of a line and how is it derived?
3. How do you find the x- and y-intercepts of a linear equation?
4. How can you determine whether two lines are parallel or perpendicular?
5. How do you solve a system of linear equations?

Tip: When converting to slope-intercept form, always rearrange the equation so that $y$ is isolated on one side for easy identification of slope and intercepts.