https://file.aiquickdraw.com/mathbot/file/1726711493250ql0cdics.jpg

Let's solve this step by step.

You are given two equations:
1. \( x = 2y - 1 \)
2. \( y = x + 20 \)

You need to substitute the first equation into the second.

### Step 1: Substitute \( x = 2y - 1 \) into \( y = x + 20 \).

\[
y = (2y - 1) + 20
\]

### Step 2: Simplify the equation.

\[
y = 2y - 1 + 20
\]
\[
y = 2y + 19
\]

### Step 3: Solve for \( y \).

Subtract \( 2y \) from both sides:

\[
y - 2y = 19
\]

\[
-y = 19
\]

Multiply both sides by -1:

\[
y = -19
\]

### Conclusion:
The correct equation resulting from the substitution is \( y = -19 \).

So the correct answer is **D**.

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Do you want more details on this solution or have any questions?

Here are some related questions for further practice:
1. How would you solve for \( x \) after finding \( y = -19 \)?
2. What happens if the equation \( y = x + 20 \) is substituted into another equation?
3. Can you graph both equations \( x = 2y - 1 \) and \( y = x + 20 \) and find their intersection point?
4. How would the solution change if the equation was \( x = 2y + 1 \) instead of \( x = 2y - 1 \)?
5. How would you approach solving the system if both equations were quadratic instead of linear?

**Tip:** Always check your final answer by substituting it back into the original equations to verify correctness.

The equation x = 2y - 1 is substituted into y = x + 20. Which of the following is the correct equation resulting from the substitution?

Learn how to solve a system of linear equations by substitution using x = 2y - 1 and y = x + 20. This detailed step-by-step guide explains the solution and helps students understand key algebraic concepts. Suitable for students in Grades 9-10.

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