The problem asks to find the equation of a line given the slope and y-intercept.

Given:

• Slope (m): 2
• y-intercept: $(0, -1)$

Solution:

The general form of the equation of a line in slope-intercept form is: $y = mx + b$ Where:

• $m$ is the slope.
• $b$ is the y-intercept.

Substituting the given values: $y = 2x - 1$

So, the equation of the line is: $\boxed{y = 2x - 1}$

Would you like more details or have any questions?

Here are 5 related questions for further practice:

1. What is the equation of a line with a slope of 3 and a y-intercept of 4?
2. How do you find the slope of a line given two points?
3. What is the equation of a line parallel to $y = 2x - 1$ but passing through $(1, 2)$?
4. If the slope is $-1/2$ and the y-intercept is 3, what is the equation of the line?
5. How does the slope affect the steepness of a line on a graph?

Tip: The y-intercept is where the line crosses the y-axis, and it occurs when $x = 0$.