To write a linear equation with a slope of 2 that passes through the point $(0, 9)$, we can use the point-slope form of a linear equation, which is:

$y - y_1 = m(x - x_1)$

Where:

• $m$ is the slope,
• $(x_1, y_1)$ is a point on the line.

In this case:

• $m = 2$,
• $(x_1, y_1) = (0, 9)$.

Substitute these values into the point-slope formula:

$y - 9 = 2(x - 0)$

Simplify:

$y - 9 = 2x$

Now, add 9 to both sides:

$y = 2x + 9$

So, the linear equation is:

$y = 2x + 9$

Would you like more details or have any other questions?

Here are some related questions for you to explore:

1. How do you find the slope of a line given two points?
2. What is the difference between point-slope form and slope-intercept form?
3. Can a linear equation have a slope of 0? What does that mean?
4. How can you determine if a point lies on a given line?
5. How do you write an equation of a line parallel or perpendicular to another line?

Tip: The slope-intercept form $y = mx + b$ is especially useful when you know the slope and the y-intercept of a line.