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The equation given is:

\[
-3 = 5x - y
\]

We need to solve for \( y \) and complete the table for the given values of \( x \). Let's rearrange the equation to isolate \( y \):

\[
y = 5x + 3
\]

Now, we can substitute the values of \( x \) into this equation to find \( y \) for each case:

1. When \( x = -1 \):
\[
y = 5(-1) + 3 = -5 + 3 = -2
\]

2. When \( x = 0 \):
\[
y = 5(0) + 3 = 0 + 3 = 3
\]

3. When \( x = 1 \):
\[
y = 5(1) + 3 = 5 + 3 = 8
\]

The completed table is:

| \( x \) | \( y \) |
|--------|--------|
|  -1    |   -2   |
|   0    |   3    |
|   1    |   8    |

Would you like further details or clarifications?

Here are 5 related questions you might find useful:
1. How do you graph the equation \( y = 5x + 3 \)?
2. What is the slope and y-intercept of the equation \( y = 5x + 3 \)?
3. How would the table change if the equation was \( y = 5x - 3 \) instead?
4. What is the meaning of the solution in the context of linear functions?
5. How do you verify your solutions by substituting the values back into the original equation?

**Tip:** Always check your solutions by plugging values of \( x \) back into the original equation to ensure consistency.

Learn how to complete a table using the linear equation -3 = 5x - y. This problem covers key algebraic concepts and is suitable for students in Grades 7-9.

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