Math Problem Statement
If C is the field of complex numbers, which vectors in C 3 are linear combinations of (1, 0, −1), (0, 1, 1), and (1, 1, 1)?
Solution
We are asked to find which vectors in (the space of 3-dimensional complex vectors) can be written as linear combinations of the three given vectors: , , and .
A vector is a linear combination of , , and if there exist complex scalars , , and such that:
This results in the following system of equations for the components of the vectors:
Now, let's solve this system for , , and in terms of , , and .
Step 1: Solve the system
- From the first equation , we can solve for :
- From the second equation , solve for :
- Substitute and into the third equation :
- Solve for :
Step 2: Find and
Now that we know , substitute this back into the expressions for and :
Step 3: Conclusion
Thus, for any vector , we can write it as a linear combination of the given vectors if and only if , , and , where , , and are complex scalars.
This means that every vector in can be expressed as a linear combination of the given three vectors, and they span . Therefore, any vector in is a linear combination of , , and .
Would you like further details on this process or clarification on any step? Here are some related questions that might help:
- How do we check if a set of vectors is linearly independent?
- What is the concept of a vector space basis, and how does it relate to this problem?
- How can we extend this idea to higher-dimensional spaces like ?
- What is the rank of a matrix, and how does it relate to the span of vectors?
- How does the solution change if we work with real numbers instead of complex numbers?
Tip: When working with linear combinations, it's helpful to start by writing out the equations clearly, then use substitution or elimination to solve for the coefficients of the linear combination.
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Math Problem Analysis
Mathematical Concepts
Linear Combinations
Vector Spaces
Complex Numbers
System of Linear Equations
Spanning Sets
Formulas
a(1, 0, -1) + b(0, 1, 1) + c(1, 1, 1) = (x, y, z)
a + c = x
b + c = y
-a + b + c = z
a = x - c
b = y - c
c = z + x - y
Theorems
Linear Combination Theorem
Spanning Set Theorem
Suitable Grade Level
Grades 11-12
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