Math Problem Statement

A bicyclist starting at rest produces a constant angular acceleration of 1.50 rad/s2 for wheels that are 34.0 cm in radius. (a) What is the bicycle's linear acceleration (in m/s2)? (Enter the magnitude.)

Solution

To find the bicycle's linear acceleration, we can use the relationship between linear acceleration (aa) and angular acceleration (α\alpha) given by the formula:

a=rαa = r \cdot \alpha

where:

  • rr is the radius of the wheels,
  • α\alpha is the angular acceleration.

Given:

  • α=1.50rad/s2\alpha = 1.50 \, \text{rad/s}^2
  • r=34.0cm=0.34mr = 34.0 \, \text{cm} = 0.34 \, \text{m} (converted to meters)

Now we can calculate the linear acceleration:

a=0.34m1.50rad/s2=0.51m/s2a = 0.34 \, \text{m} \cdot 1.50 \, \text{rad/s}^2 = 0.51 \, \text{m/s}^2

Thus, the bicycle's linear acceleration is 0.51 m/s².

Would you like further details or have any questions? Here are some related questions you might consider:

  1. How does the linear acceleration change with a different angular acceleration?
  2. What is the relationship between linear and angular velocity?
  3. How would you calculate the distance traveled by the bicycle in a given time?
  4. What factors can affect the angular acceleration of the bicycle's wheels?
  5. How does the size of the wheel influence the bicycle's performance?

Tip: Always convert units to the SI system before performing calculations to ensure consistency.

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Math Problem Analysis

Mathematical Concepts

Physics
Kinematics
Rotational Motion

Formulas

a = r * α

Theorems

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Suitable Grade Level

Grades 9-12