A bicyclist starting at rest produces a constant angular acceleration of 1.50 rad/s2 for wheels that are 34.0 cm in radius.
(a) What is the bicycle's linear acceleration (in m/s2)? (Enter the magnitude.)

To find the bicycle's linear acceleration, we can use the relationship between linear acceleration (\(a\)) and angular acceleration (\(\alpha\)) given by the formula:

\[
a = r \cdot \alpha
\]

where:
- \(r\) is the radius of the wheels,
- \(\alpha\) is the angular acceleration.

Given:
- \(\alpha = 1.50 \, \text{rad/s}^2\)
- \(r = 34.0 \, \text{cm} = 0.34 \, \text{m}\) (converted to meters)

Now we can calculate the linear acceleration:

\[
a = 0.34 \, \text{m} \cdot 1.50 \, \text{rad/s}^2 = 0.51 \, \text{m/s}^2
\]

Thus, the bicycle's linear acceleration is **0.51 m/s²**.

Would you like further details or have any questions? Here are some related questions you might consider:

1. How does the linear acceleration change with a different angular acceleration?
2. What is the relationship between linear and angular velocity?
3. How would you calculate the distance traveled by the bicycle in a given time?
4. What factors can affect the angular acceleration of the bicycle's wheels?
5. How does the size of the wheel influence the bicycle's performance? 

**Tip:** Always convert units to the SI system before performing calculations to ensure consistency.

A bicyclist starting at rest produces a constant angular acceleration of 1.50 rad/s2 for wheels that are 34.0 cm in radius. (a) What is the bicycle's linear acceleration (in m/s2)? (Enter the magnitude.)

Discover how to calculate the linear acceleration of a bicycle starting from rest with a constant angular acceleration of 1.50 rad/s² and wheel radius of 34.0 cm. The solution explains the relationship between linear and angular acceleration. Suitable for high school students.

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