To find the Line of Best Fit, we will use the least squares method to determine the best linear relationship between the variables x and y. The formula for the line of best fit is y=mx+b, where m is the slope and b is the y-intercept.
Given the data points:
x:7.2,2.9,4.8,7.1,3.2,3.8,7.6
y:19,10,14.1,19.3,11.4,13.6,21
Let's calculate the necessary components step-by-step.
- Calculate the means of x and y:
xˉ=77.2+2.9+4.8+7.1+3.2+3.8+7.6
xˉ=736.6
xˉ≈5.23
yˉ=719+10+14.1+19.3+11.4+13.6+21
yˉ=7108.4
yˉ≈15.49
- Calculate the slope m:
m=∑(xi−xˉ)2∑(xi−xˉ)(yi−yˉ)
Calculate each term:
(xi−xˉ)(yi−yˉ)
(7.2−5.23)(19−15.49)=1.97×3.51=6.91
(2.9−5.23)(10−15.49)=−2.33×−5.49=12.79
(4.8−5.23)(14.1−15.49)=−0.43×−1.39=0.60
(7.1−5.23)(19.3−15.49)=1.87×3.81=7.12
(3.2−5.23)(11.4−15.49)=−2.03×−4.09=8.30
(3.8−5.23)(13.6−15.49)=−1.43×−1.89=2.70
(7.6−5.23)(21−15.49)=2.37×5.51=13.07
Sum of (xi−xˉ)(yi−yˉ):
∑(xi−xˉ)(yi−yˉ)=6.91+12.79+0.60+7.12+8.30+2.70+13.07
∑(xi−xˉ)(yi−yˉ)=51.49
Calculate each term:
(xi−xˉ)2
(7.2−5.23)2=1.972=3.88
(2.9−5.23)2=(−2.33)2=5.43
(4.8−5.23)2=(−0.43)2=0.18
(7.1−5.23)2=1.872=3.50
(3.2−5.23)2=(−2.03)2=4.12
(3.8−5.23)2=(−1.43)2=2.05
(7.6−5.23)2=2.372=5.62
Sum of (xi−xˉ)2:
∑(xi−xˉ)2=3.88+5.43+0.18+3.50+4.12+2.05+5.62
∑(xi−xˉ)2=24.78
m=24.7851.49
m≈2.08
- Calculate the y-intercept b:
b=yˉ−mxˉ
b=15.49−(2.08×5.23)
b=15.49−10.88
b≈4.61
Therefore, the Line of Best Fit is:
y=2.08x+4.61
Would you like more details or have any questions?
Here are five related questions:
- How would you calculate the correlation coefficient for this data?
- What is the significance of the slope in the line of best fit?
- How can we interpret the y-intercept in this context?
- What are residuals, and how can they be used to assess the fit of the line?
- How would adding more data points affect the line of best fit?
Tip: Always plot your data and the line of best fit to visually assess the accuracy and fit of the model.