Math Problem Statement

Use linear regression to find the line of best fit for the given data.

Use the given variables in your answer. Round to 3 decimal places as needed.

x= 1 2 3 4 5 6 y= 536 518 547 523 547 567

Solution

To find the line of best fit using linear regression, we need to calculate the slope (m) and y-intercept (b) of the line:

The equation of the line of best fit is:

y=mx+by = mx + b

Where:

  • mm is the slope of the line,
  • bb is the y-intercept.

Steps to find the linear regression line:

  1. Calculate the averages:

    • Mean of xx: xˉ\bar{x}
    • Mean of yy: yˉ\bar{y}
  2. Find the slope (mm): m=n(xy)xynx2(x)2m = \frac{n \sum{(xy)} - \sum{x} \sum{y}}{n \sum{x^2} - (\sum{x})^2} Where:

    • nn is the number of data points (in this case, n=6n = 6),
    • xy\sum{xy} is the sum of the products of corresponding values of xx and yy,
    • x\sum{x} is the sum of the xx-values,
    • y\sum{y} is the sum of the yy-values,
    • x2\sum{x^2} is the sum of the squared xx-values.
  3. Find the y-intercept (bb): b=yˉmxˉb = \bar{y} - m \bar{x}

Let's calculate the values step-by-step.

Step 1: Calculate the necessary sums

Given data:

  • x=[1,2,3,4,5,6]x = [1, 2, 3, 4, 5, 6]
  • y=[536,518,547,523,547,567]y = [536, 518, 547, 523, 547, 567]

We will compute the sums:

  • x=1+2+3+4+5+6=21\sum{x} = 1 + 2 + 3 + 4 + 5 + 6 = 21
  • y=536+518+547+523+547+567=3238\sum{y} = 536 + 518 + 547 + 523 + 547 + 567 = 3238
  • x2=12+22+32+42+52+62=1+4+9+16+25+36=91\sum{x^2} = 1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2 = 1 + 4 + 9 + 16 + 25 + 36 = 91
  • xy=(1)(536)+(2)(518)+(3)(547)+(4)(523)+(5)(547)+(6)(567)=536+1036+1641+2092+2735+3402=9442\sum{xy} = (1)(536) + (2)(518) + (3)(547) + (4)(523) + (5)(547) + (6)(567) = 536 + 1036 + 1641 + 2092 + 2735 + 3402 = 9442

Step 2: Apply the formula for slope mm

m=6(9442)(21)(3238)6(91)(21)2m = \frac{6(9442) - (21)(3238)}{6(91) - (21)^2} m=5665267998546441m = \frac{56652 - 67998}{546 - 441} m=11346105m = \frac{-11346}{105} m107.8m \approx -107.8

Step 3: Apply the formula for intercept bb

xˉ=xn=216=3.5\bar{x} = \frac{\sum{x}}{n} = \frac{21}{6} = 3.5 yˉ=yn=32386539.67\bar{y} = \frac{\sum{y}}{n} = \frac{3238}{6} \approx 539.67 b=yˉmxˉb = \bar{y} - m\bar{x} b=539.67(107.8)(3.5)b = 539.67 - (-107.8)(3.5) b=539.67+377.3b = 539.67 + 377.3 b916.97b \approx 916.97

Final Answer:

The line of best fit is approximately:

y=107.8x+916.97y = -107.8x + 916.97


Would you like further explanation on any part of the solution or more questions about linear regression? Here are some related questions you can explore:

  1. How would you interpret the slope and intercept in this context?
  2. What is the coefficient of determination (R2R^2) and how is it calculated?
  3. How can we assess the goodness of fit for the regression model?
  4. How would the line of best fit change if you added another data point to the dataset?
  5. How would you predict yy for x=7x = 7 using the equation of the line?

Tip: When interpreting the slope, keep in mind that it shows how much yy changes for a one-unit change in xx.

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Math Problem Analysis

Mathematical Concepts

Linear Regression
Statistics
Algebra

Formulas

y = mx + b
m = (n Σ(xy) - Σx Σy) / (n Σx^2 - (Σx)^2)
b = ȳ - m * x̄

Theorems

Least Squares Method

Suitable Grade Level

Grades 9-12