Math Problem Statement

Question content area top Part 1 Use the following function to answer questions ​(​a) and ​(b​) below. ​f(x)equals= left brace Start 2 By 2 Matrix 1st Row 1st Column 8 minus x comma 2nd Column x less than 4 2nd Row 1st Column StartFraction x Over 2 EndFraction plus 3 comma 2nd Column x greater than 4 EndMatrix 8−x, x<4 x 2+3, x>4 Question content area bottom Part 1 ​(a) Find ModifyingBelow lim With x right arrow 4 Superscript plus f left parenthesis x right parenthesislimx→4+f(x) and ModifyingBelow lim With x right arrow 4 Superscript minus f left parenthesis x right parenthesislimx→4−f(x). Select the correct choice below and fill in any answer​ box(es) in your choice. ​(Simplify your​ answers.) A. ModifyingBelow lim With x right arrow 4 Superscript plus f left parenthesis x right parenthesislimx→4+f(x)equals=55​, ModifyingBelow lim With x right arrow 4 Superscript minus f left parenthesis x right parenthesislimx→4−f(x)equals=44 Your answer is correct.B. ModifyingBelow lim With x right arrow 4 Superscript plus f left parenthesis x right parenthesislimx→4+f(x) does not​ exist, ModifyingBelow lim With x right arrow 4 Superscript minus f left parenthesis x right parenthesislimx→4−f(x)equals= enter your response here C. ModifyingBelow lim With x right arrow 4 Superscript plus f left parenthesis x right parenthesislimx→4+f(x)equals= enter your response here​, ModifyingBelow lim With x right arrow 4 Superscript minus f left parenthesis x right parenthesislimx→4−f(x) does not exist D. The limits do not exist. Part 2 ​(b) Does ModifyingBelow lim With x right arrow 4 f left parenthesis x right parenthesislimx→4f(x) ​exist? If​ so, what is​ it? If​ not, why​ not? A. ​No, ModifyingBelow lim With x right arrow 4 f left parenthesis x right parenthesislimx→4f(x) does not exist because f left parenthesis 4 right parenthesisf(4) is undefined. B. ​No, ModifyingBelow lim With x right arrow 4 f left parenthesis x right parenthesislimx→4f(x) does not exist because ModifyingBelow lim With x right arrow 4 Superscript plus f left parenthesis x right parenthesislimx→4+f(x)not equals≠ModifyingBelow lim With x right arrow 4 Superscript minus f left parenthesis x right parenthesislimx→4−f(x). C. ​Yes, ModifyingBelow lim With x right arrow 4 f left parenthesis x right parenthesislimx→4f(x) exists and equals

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Math Problem Analysis

Mathematical Concepts

Limits
Piecewise Functions

Formulas

lim(x→c+) f(x)
lim(x→c−) f(x)

Theorems

Limit Existence Theorem

Suitable Grade Level

Grades 11-12