Math Problem Statement

Given the graph of f(x), evaluate the following, if they exist. If a limit does not exist, write DNE, ∞, or -∞ as appropriate. No work needs to be shown here.

Solution

Let's analyze the graph of f(x)f(x) based on the given image to answer the questions.

(a) f(3)f(-3)

At x=3x = -3, the graph shows a point at approximately y=6y = 6.

  • Answer: 6

(b) f(2)f(2)

At x=2x = 2, the function is undefined since there is no closed dot on the graph at x=2x = 2.

  • Answer: DNE (Does Not Exist)

(c) limx3f(x)\lim_{x \to -3} f(x)

The limit as x3x \to -3 from both sides approaches the value of the function at x=3x = -3, which is 6.

  • Answer: 6

(d) limx3+f(x)\lim_{x \to -3^+} f(x)

As xx approaches 3-3 from the right, the graph approaches the point y=6y = 6.

  • Answer: 6

(e) limx2f(x)\lim_{x \to -2} f(x)

As xx approaches 2-2 from both sides, the function value approaches 2.

  • Answer: 2

(f) limx2+f(x)\lim_{x \to -2^+} f(x)

As xx approaches 2-2 from the right, the graph still approaches 2.

  • Answer: 2

(g) limx2f(x)\lim_{x \to -2^-} f(x)

As xx approaches 2-2 from the left, the limit is also 2.

  • Answer: 2

(h) limx2f(x)\lim_{x \to -2} f(x) (repeated)

This is the same as (e).

  • Answer: 2

(i) limx2f(x)\lim_{x \to 2^-} f(x)

As xx approaches 2 from the left, the function approaches negative infinity.

  • Answer: -\infty

(j) limx2+f(x)\lim_{x \to 2^+} f(x)

As xx approaches 2 from the right, the function approaches positive infinity.

  • Answer: ++\infty

(k) limx5f(x)\lim_{x \to -5} f(x)

As xx approaches 5-5, the function approaches negative infinity.

  • Answer: -\infty

(l) limx5+f(x)\lim_{x \to 5^+} f(x)

As xx approaches 5 from the right, the graph behaves erratically (oscillates), so the limit does not exist.

  • Answer: DNE

(m) limx5f(x)\lim_{x \to 5} f(x)

The function oscillates heavily near x=5x = 5, indicating the limit does not exist.

  • Answer: DNE

(n) limx7f(x)\lim_{x \to 7} f(x)

As xx approaches 77, the function value approaches y=2y = 2.

  • Answer: 2

(o) Vertical Asymptotes

Vertical asymptotes exist where the function tends to \infty or -\infty. From the graph, there appears to be a vertical asymptote at x=2x = 2.

  • Answer: x=2x = 2

Let me know if you'd like further clarification on any of these answers.

Follow-up questions:

  1. What are the general conditions for a limit to exist?
  2. How does the behavior of the function near x=5x = 5 lead to a "does not exist" limit?
  3. How do we identify vertical asymptotes on a graph?
  4. Why does the limit approach infinity at x=2x = 2?
  5. What other types of discontinuities can a function have?

Tip: A limit exists only if the left-hand and right-hand limits are equal at a given point.

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Math Problem Analysis

Mathematical Concepts

Limits
Continuity
Vertical Asymptotes
Function Evaluation
One-sided Limits

Formulas

Limits of a function as x approaches a point
One-sided limits
Identification of vertical asymptotes

Theorems

Limits of Functions
Continuity and Discontinuity Theorems
Vertical Asymptotes Theorem

Suitable Grade Level

Grades 11-12