Math Problem Statement

In GUESA Format (Given, Unknown, Equation, Solution, Answer)

Consider this reaction: 3H2(g) + N2(g) --> 2NH3(g)

part I. If 6.60 moles H2(hydrogen gas) are made to react with 4.42 moles N2 (nitrogen gas).

  1. what is the limiting reagent?
  2. How many moles NH3(ammonia) will be produced?
  3. What reagent is in excess and by how much?

Solution

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Stoichiometry
Mole Ratio
Limiting Reagent

Formulas

Mole ratio from balanced equation: 3H2 : 1N2 --> 2NH3
Limiting reagent calculation: moles of each reactant divided by their coefficients
Excess reagent calculation: initial moles - moles reacted

Theorems

Law of Conservation of Mass
Stoichiometric Calculations

Suitable Grade Level

Grades 10-12

Related Recommendation

Nitrogen and Hydrogen Reaction - Limiting Reactants and Ammonia Production

Limiting Reactant, Percent Excess, and Percent Conversion in Ammonia Synthesis

Calculate Ammonia Mass in Haber Process Reaction at 294 K and 0.94 bar

Limiting Reactant Calculation: H2 and O2 Reaction to Form Water

Calculate N₂ Volume for Haber Process Reaction