Math Problem Statement

In GUESA Format (Given, Unknown, Equation, Solution, Answer)

Consider this reaction: 3H2(g) + N2(g) --> 2NH3(g)

part I. If 6.60 moles H2(hydrogen gas) are made to react with 4.42 moles N2 (nitrogen gas).

  1. what is the limiting reagent?
  2. How many moles NH3(ammonia) will be produced?
  3. What reagent is in excess and by how much?

Solution

Let's break this problem down step by step in the GUESA format:

Part I:

Reaction: 3H2(g)+N2(g)→2NH3(g)3H_2(g) + N_2(g) \rightarrow 2NH_3(g)

1. Limiting Reagent

Given:

  • Moles of (

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Math Problem Analysis

Mathematical Concepts

Stoichiometry
Mole Ratio
Limiting Reagent

Formulas

Mole ratio from balanced equation: 3H2 : 1N2 --> 2NH3
Limiting reagent calculation: moles of each reactant divided by their coefficients
Excess reagent calculation: initial moles - moles reacted

Theorems

Law of Conservation of Mass
Stoichiometric Calculations

Suitable Grade Level

Grades 10-12

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