Math Problem Statement

Вычислить предел, используя разложения функций по формуле Тейлора или Маклорена

Вычислить предел, используя разложения функций по формуле Тейлора или Маклорена

Solution

from sympy import symbols, limit, cos, asin, sqrt, series

Define the variable

x = symbols('x')

Define the expressions

numerator = 5 * x denominator = asin(x)5 inner_expr = 6 / (3 + x2) - sqrt(cos(2 * x)) expr = inner_expr * (numerator / denominator)

Expand using series for Taylor approximations

expanded_inner = series(6 / (3 + x**2) - sqrt(cos(2 * x)), x, 0, 5).removeO() expanded_arcsin = series(asin(x), x, 0, 5).removeO()**5

Simplify the limit calculation

simplified_expr = expanded_inner * (numerator / expanded_arcsin)

Compute the limit

result = limit(simplified_expr, x, 0) resultoooosuccessThe limit of the given expression diverges to infinity (\infty). This indicates that the expression becomes unbounded as x0x \to 0.

Let me know if you want a detailed explanation of the steps, or feel free to ask additional questions. Here are 5 related questions for practice:

  1. How do Taylor or Maclaurin series help in simplifying limits involving transcendental functions?
  2. Can we analyze the individual contributions to the divergence in this expression?
  3. What happens if we replace arcsin(x)\arcsin(x) with a simpler function, like xx?
  4. How would the series expansion change if a higher-order approximation were used?
  5. Can L’Hôpital’s rule provide an alternative approach to verify the divergence?

Tip: Always check if your function has terms with a faster rate of growth (or decay) to detect divergence/convergence tendencies early.

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Math Problem Analysis

Mathematical Concepts

Limits
Taylor Series
Maclaurin Series
Transcendental Functions

Formulas

Maclaurin series expansion for transcendental functions
Taylor series for functions around x = 0
Basic trigonometric limits

Theorems

Maclaurin Series Theorem
Taylor Series Expansion
Limit Properties

Suitable Grade Level

Undergraduate (Calculus Level)