It looks like you want to evaluate the limit of an expression involving trigonometric functions. I assume your expression is:

$\lim_{x \to 0} \frac{\sin^2(x)}{x^2}$

Let’s break this down:

We can use the known limit:

$\lim_{x \to 0} \frac{\sin(x)}{x} = 1$

This means that:

$\lim_{x \to 0} \frac{\sin^2(x)}{x^2} = \left(\lim_{x \to 0} \frac{\sin(x)}{x}\right)^2 = 1^2 = 1$

Thus, the limit is:

$\boxed{1}$

Do you want more details or have any other questions?

Here are five related questions:

1. How do you evaluate limits of trigonometric functions as $x \to \infty$?
2. What is the limit of $\frac{\sin(x)}{x}$ as $x$ approaches infinity?
3. How do you evaluate limits involving $\tan(x)$ or $\cos(x)$?
4. How do you apply L'Hopital's Rule to limits like this?
5. How would this change if $\sin^2(x)$ was replaced by $\cos^2(x)$?

Tip: Memorizing common trigonometric limits, like $\lim_{x \to 0} \frac{\sin(x)}{x} = 1$, can make solving limit problems faster and easier!