To find the limit of the given function as $t \to 2$:

$\lim_{t \to 2} (6t^2 - 3t + 1)$

We can substitute $t = 2$ directly into the expression, since the function is a polynomial and continuous everywhere.

$6(2)^2 - 3(2) + 1 = 6(4) - 6 + 1 = 24 - 6 + 1 = 19$

Thus, the limit is:

$\lim_{t \to 2} (6t^2 - 3t + 1) = 19$

Would you like a more detailed explanation or have any questions?

Here are five related questions for further practice:

1. What is $\lim_{t \to 3} (5t^2 - 2t + 4)$?
2. How would you evaluate $\lim_{x \to -1} (x^3 + 4x^2 - x + 6)$?
3. What is the limit of $\lim_{x \to 0} (2x^2 - 3x + 1)$?
4. Can you compute $\lim_{t \to 5} (3t^2 + 7t - 2)$?
5. How do you find $\lim_{x \to 2} (4x^3 - 2x + 3)$?

Tip: Polynomials are continuous everywhere, so direct substitution is a valid method for finding limits involving polynomials.