To compute the limit $\lim_{x \to 1} (2x - 2)^3$, we can directly substitute $x = 1$ into the expression since the function is continuous at $x = 1$.

Let's go through the steps:

1. First, simplify the expression inside the cube: $2x - 2 = 2(1) - 2 = 0$

2. Now, take the cube of the result: $(2x - 2)^3 = 0^3 = 0$

Therefore, the limit is:

$\lim_{x \to 1} (2x - 2)^3 = 0$

Would you like more details on limits or have any questions?

Here are 5 related questions:

1. How do you compute limits for functions that are not continuous?
2. What happens when the limit leads to an indeterminate form like $\frac{0}{0}$?
3. Can you explain the difference between one-sided and two-sided limits?
4. How do we evaluate limits involving infinity?
5. When should we use L'Hopital's Rule for limits?

Tip: For polynomial and rational functions, direct substitution often works to compute limits if the function is continuous at the point of interest.