The limit you're asking for is:

$\lim_{x \to 0} \sec(x)$

First, recall the definition of the secant function:

$\sec(x) = \frac{1}{\cos(x)}$

As $x \to 0$, we know that:

$\cos(0) = 1$

Thus:

$\sec(0) = \frac{1}{\cos(0)} = \frac{1}{1} = 1$

Therefore, the limit is:

$\lim_{x \to 0} \sec(x) = 1$

Would you like further details or have any questions?

Here are 5 related questions for further exploration:

1. What is the limit of $\sec(x)$ as $x \to \pi/2$?
2. How does $\sec(x)$ behave near asymptotes?
3. What is the derivative of $\sec(x)$?
4. How can we calculate $\lim_{x \to 0} \csc(x)$?
5. What is the Taylor series expansion of $\sec(x)$ around $x = 0$?

Tip: For trigonometric functions, it's always helpful to remember key values and behaviors at important points like 0, $\pi/2$, and $\pi$.