Math Problem Statement

lim ((a^x+b^x+c^x)/3)^1/x as x->0

Solution

We are tasked with finding the limit:

limx0(ax+bx+cx3)1x\lim_{{x \to 0}} \left( \frac{a^x + b^x + c^x}{3} \right)^{\frac{1}{x}}

Step-by-step analysis:

  1. Examine the base expression: The expression inside the limit is: (ax+bx+cx3)1x\left( \frac{a^x + b^x + c^x}{3} \right)^{\frac{1}{x}} As x0x \to 0, we note that for any positive real number aa, axa^x approaches 1, because ax=exlnaa^x = e^{x \ln a} and as x0x \to 0, xlna0x \ln a \to 0. Therefore: ax1,bx1,cx1asx0.a^x \to 1, \quad b^x \to 1, \quad c^x \to 1 \quad \text{as} \quad x \to 0.

  2. Simplify the limit expression: As x0x \to 0, ax+bx+cx3a^x + b^x + c^x \to 3, so the base of the expression approaches: ax+bx+cx31+1+13=1.\frac{a^x + b^x + c^x}{3} \to \frac{1 + 1 + 1}{3} = 1.

  3. Apply the limit: The expression then becomes: (ax+bx+cx3)1x11x.\left( \frac{a^x + b^x + c^x}{3} \right)^{\frac{1}{x}} \to 1^{\frac{1}{x}}. Since 11x=11^{\frac{1}{x}} = 1 for any xx, the limit is simply: limx01=1.\lim_{{x \to 0}} 1 = 1.

Thus, the final result is:

1.\boxed{1}.

Would you like more details, or do you have any questions about this solution?

Here are 5 related questions for practice:

  1. What is the limit limx0ax\lim_{{x \to 0}} a^x for a>0a > 0?
  2. How do you compute limx0(ax+bx2)1/x\lim_{{x \to 0}} \left( \frac{a^x + b^x}{2} \right)^{1/x}?
  3. What is the behavior of axa^x as xx \to \infty for a>1a > 1?
  4. What is the limit of (ex+12)1/x\left( \frac{e^x + 1}{2} \right)^{1/x} as x0x \to 0?
  5. How do you compute the limit limx0(axx)\lim_{{x \to 0}} \left( \frac{a^x}{x} \right)?

Tip: When dealing with limits involving powers, it's helpful to rewrite expressions using logarithms for easier evaluation.

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Math Problem Analysis

Mathematical Concepts

Limits
Exponential Functions
Algebra

Formulas

lim (a^x + b^x + c^x)/3 as x -> 0
a^x = e^(x ln a)
lim 1^(1/x) = 1

Theorems

Exponential Limit Theorem
Properties of Limits

Suitable Grade Level

Grades 11-12