Math Problem Statement

lim of x approfhes to negative 0 from 1/x sqare ori e at 1/x and then for f(x)=m find the real values of m for each the equations has exactly 3 real solutions

Solution

Let's break this problem into two parts and solve them step-by-step.

Part 1: Finding the Limit

First, we need to find the limit of 1x2\frac{1}{x^2} as xx approaches 00 from the negative side.

limx01x2\lim_{{x \to 0^-}} \frac{1}{x^2}

The function 1x2\frac{1}{x^2} is defined as xx approaches 00 from the negative side. Notice that x2x^2 is always positive regardless of the sign of xx. As xx approaches 00 from the negative side, x2x^2 approaches 00 and hence 1x2\frac{1}{x^2} becomes infinitely large. Therefore, the limit is:

limx01x2=\lim_{{x \to 0^-}} \frac{1}{x^2} = \infty

Part 2: Finding mm for Exactly 3 Real Solutions

Next, we need to determine the real values of mm for which the equation f(x)=mf(x) = m has exactly three real solutions, given the function f(x)f(x).

Assume f(x)=1xf(x) = \frac{1}{x}. We need to find the real values of mm for which the equation 1x=m\frac{1}{x} = m has exactly three real solutions.

The equation 1x=m\frac{1}{x} = m simplifies to:

x=1mx = \frac{1}{m}

For this equation to have exactly three real solutions, we need a bit more information or a different form of the function f(x)f(x). However, based on the standard interpretation of the problem and usual functions, let's assume f(x)=x3f(x) = x^3. In this case, the equation becomes:

x3=mx^3 = m

The cubic function x3=mx^3 = m will intersect a horizontal line y=my = m exactly three times if and only if m=0m = 0 (which means the line touches the origin where the function has an inflection point). Otherwise, for a typical cubic polynomial, the intersections depend on the specific form of the function. However, given the typical cubic polynomial scenario, m=0m = 0 is the special case that we need. Hence, there is only one mm:

m=0m = 0

Summary

  1. The limit as xx approaches 00 from the negative side of 1x2\frac{1}{x^2} is \infty.
  2. For the function f(x)=x3f(x) = x^3, the value of mm for which the equation f(x)=mf(x) = m has exactly three real solutions is m=0m = 0.

Would you like more details or have any questions about these solutions? Here are 5 additional questions you might consider:

  1. How do we find the limits of more complex functions?
  2. What are the properties of cubic functions and their roots?
  3. How do you solve equations involving higher-degree polynomials?
  4. Can you explain how the Intermediate Value Theorem helps in finding roots?
  5. What is the significance of inflection points in polynomial functions?

Tip: When dealing with limits involving infinity, always consider the behavior of the function as it approaches the point from both sides to understand the full behavior of the function.

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Math Problem Analysis

Mathematical Concepts

Limits
Cubic Functions
Real Solutions

Formulas

Limit definition
Cubic function

Theorems

Intermediate Value Theorem

Suitable Grade Level

Grades 10-12