Math Problem Statement

If a single pane of glass obliterates 3​% of the light passing through​ it, the percent p of light that passes through n successive panes is given approximately by the function below. p left parenthesis n right parenthesis equals 100 left parenthesis 0.97 right parenthesis Superscript n ​(a) What percent of light will pass through 5 ​panes? ​(b) What percent of light will pass through 10 ​panes? ​(c) Explain the meaning of the base 0.97 in this problem. Question content area bottom Part 1 ​(a) The percent of light that will pass through 5 panes is approximately

enter your response here​%. ​(Round to the nearest whole number as​ needed.)

Solution

We are given the function for the percentage of light that passes through nn successive panes of glass:

p(n)=100×(0.97)np(n) = 100 \times (0.97)^n

(a) The percent of light that will pass through 5 panes:

Substitute n=5n = 5 into the equation:

p(5)=100×(0.97)5p(5) = 100 \times (0.97)^5

First, calculate (0.97)5(0.97)^5:

(0.97)50.8587(0.97)^5 \approx 0.8587

Now multiply by 100 to get the percentage:

p(5)=100×0.8587=85.87p(5) = 100 \times 0.8587 = 85.87

Rounding to the nearest whole number:

p(5)86%p(5) \approx 86\%

So, approximately 86% of light will pass through 5 panes.


(b) The percent of light that will pass through 10 panes:

Substitute n=10n = 10 into the equation:

p(10)=100×(0.97)10p(10) = 100 \times (0.97)^{10}

First, calculate (0.97)10(0.97)^{10}:

(0.97)100.7374(0.97)^{10} \approx 0.7374

Now multiply by 100:

p(10)=100×0.7374=73.74p(10) = 100 \times 0.7374 = 73.74

Rounding to the nearest whole number:

p(10)74%p(10) \approx 74\%

So, approximately 74% of light will pass through 10 panes.


(c) The meaning of the base 0.97:

The base 0.970.97 represents the percentage of light that passes through a single pane of glass. Specifically, it means that 97% of the light passes through one pane, and 3% of the light is absorbed or blocked by the pane. The exponential function then models how this 97% transmission factor compounds as light passes through multiple panes.


Do you have any further questions or want more details?

Here are some related questions to expand on this:

  1. How does the percent of light change as the number of panes increases?
  2. What would happen to the light transmission if each pane blocked 5% of the light?
  3. Can you derive the percent of light that passes through 15 panes?
  4. How would the function change if 4% of light was absorbed per pane?
  5. What is the total percentage of light blocked by 8 panes?

Tip: In problems involving successive multiplications (like repeated percentages), exponential functions are often used to model the compound effect!

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Math Problem Analysis

Mathematical Concepts

Exponential Decay
Percentage Calculations

Formulas

p(n) = 100 * (0.97)^n

Theorems

Exponential Decay Function

Suitable Grade Level

Grades 9-10