The problem asks you to calculate how many license plates can be generated with a format of three digits followed by three letters. The conditions provided are:

• The digits can be any of the digits from 0 to 9, excluding 4 and 5, so there are 8 possible digits.
• There are 26 possible letters (A to Z).
• The digits and letters can be repeated.

To calculate the total number of possible license plates:

1. For the digits: There are 8 choices for each digit, and there are three digits in the license plate.

   • The number of possible ways to choose the digits is $8 \times 8 \times 8 = 8^3 = 512$.

2. For the letters: There are 26 choices for each letter, and there are three letters in the license plate.

   • The number of possible ways to choose the letters is $26 \times 26 \times 26 = 26^3 = 17,576$.

Finally, multiply the number of possible digits by the number of possible letters to get the total number of license plates:

$512 \times 17,576 = 8,993,792$

Thus, 8,993,792 different license plates can be generated.

Do you need any further clarifications or details on the solution?

Here are some related questions you might find interesting:

1. What would happen if the digits could not be repeated?
2. How many license plates can be generated if the format were changed to two digits followed by four letters?
3. If additional restrictions were imposed on the letters (e.g., only vowels can be used), how would that affect the total number of plates?
4. How would the solution change if the digits and letters could not be repeated at all?
5. What other counting principles could be applied to solve variations of this problem?

Tip: Always double-check the total number of available choices for each part of a problem before multiplying them together.