To create an equation based on your scenario, we start by defining the variables:

• Let $w$ be the width of the rectangle.
• Since the length $l$ is 3 times the width, we can express it as $l = 3w$.

The area $A$ of a rectangle is given by the formula:

$A = l \times w$

Substituting the expressions we have:

$300 = (3w) \times w$

This simplifies to:

$300 = 3w^2$

Now, we can solve for $w$:

1. Divide both sides by 3:

$100 = w^2$

2. Take the square root of both sides:

$w = 10 \quad (\text{since width cannot be negative})$

Now we can find the length:

$l = 3w = 3 \times 10 = 30$

Therefore, the length of the rectangle is 30 feet.

If you need more details or have any questions, feel free to ask! Here are some related questions to consider:

1. How would the area change if the width is doubled?
2. What is the perimeter of the rectangle?
3. How would the dimensions change if the area were 400 square feet instead?
4. What would the dimensions be if the length was only twice the width?
5. How does changing the width affect the area for a fixed length?

Tip: Always double-check your units when calculating areas to ensure they are consistent!