What least number must be subtracted from 2716321 to make it exactly
divisible by 3456?

To find the least number that must be subtracted from 2,716,321 to make it divisible by 3,456, we can follow these steps:

### Steps:
1. **Divide 2,716,321 by 3,456** to find the remainder.
2. **Subtract the remainder** from 2,716,321 to make it exactly divisible.

Let's calculate it.

First, perform the division:

\[
2716321 \div 3456 = 786.0289...
\]

Now, let's find the remainder by multiplying the integer part back:

\[
786 \times 3456 = 2716416
\]

Now subtract 2,716,321 from 2,716,416:

\[
2716416 - 2716321 = 95
\]

### Result:
The least number to be subtracted is **95**.

By subtracting 95 from 2,716,321, the result will be divisible by 3,456.

Would you like more details or explanations on any step?

Here are some related questions:
1. What if the number to divide by was a prime number?
2. How to handle cases when a number is divisible by multiple divisors?
3. Can this be done for negative numbers as well?
4. What is the largest number that can divide both 2716321 and 3456?
5. How can this process be done using modular arithmetic?

**Tip:** When dividing to find remainders, working with the floor or integer division can save you time.

What least number must be subtracted from 2716321 to make it exactly divisible by 3456?

Learn how to find the least number that must be subtracted from 2,716,321 to make it exactly divisible by 3,456. This solution uses basic number theory concepts, including division with remainder, and is suitable for students in Grades 6-8.

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