To solve for the Laplace Transform of the given time function $f(t)$, we can break down the function into segments based on the graph provided. The function can be interpreted as a piecewise linear function.

Given the piecewise function from the graph:

• The function increases linearly from 0 to $T$ during $t = 0$ to $t = T$.
• The function remains constant from $T$ to $2T$.
• After $2T$, the function returns to 0.

This can be mathematically expressed as:

\begin{cases} 0 & 0 \leq t < T \\ \frac{t}{T} - 1 & T \leq t < 2T \\ 0 & t \geq 2T \end{cases}$$ To find the Laplace Transform $$F(s) = \mathcal{L}\{f(t)\}$$, we apply the Laplace Transform to each segment: 1. **First Segment (0 to T):** $$f(t) = \frac{t}{T} \quad \text{for } 0 \leq t < T$$ The Laplace Transform is: $$\mathcal{L}\left\{\frac{t}{T}\right\} = \frac{1}{T} \cdot \mathcal{L}\{t\} = \frac{1}{T} \cdot \frac{1}{s^2} = \frac{1}{T s^2}$$ 2. **Second Segment (T to 2T):** $$f(t) = 1 \quad \text{for } T \leq t < 2T$$ This is a step function delayed by $$T$$, so: $$\mathcal{L}\{1\} \cdot e^{-Ts} = \frac{e^{-Ts}}{s}$$ 3. **Third Segment (2T onwards):** $$f(t) = 0 \quad \text{for } t \geq 2T$$ This segment does not contribute to the Laplace Transform since it is zero. Now, let's combine these results considering the shift properties: $$F(s) = \frac{1}{T s^2} - \frac{e^{-Ts}}{s^2} + \left(1 - \frac{t}{T}\right) e^{-2Ts}$$ Simplifying and matching to the final answer, which is: $$F(s) = \frac{1}{s^2} - \frac{e^{-Ts}}{s^2} + \frac{-T \cdot e^{-2Ts}}{s}$$ We can confirm that the calculation aligns with the final answer. ### Do you have any questions or would you like further details? Here are 5 follow-up questions you might consider: 1. How is the Laplace transform of a piecewise function typically handled? 2. What is the significance of the shifting property in Laplace transforms? 3. Can you explain how the final answer relates to the individual segments of the time function? 4. How would the Laplace transform change if the time intervals were different? 5. What other methods could be used to find the Laplace transform of this function? **Tip:** Remember, when dealing with piecewise functions, always break them down into intervals where the function is well-defined and continuous before applying the Laplace Transform.