Math Problem Statement

Minimize f(x,y) = 48x +96y -x^2 -2xy-9y^2 subject to the consstraint 20x+4y=216 .Use Lagrange multipliers to find the value

Solution

To minimize the function f(x,y)=48x+96yx22xy9y2f(x, y) = 48x + 96y - x^2 - 2xy - 9y^2 subject to the constraint 20x+4y=21620x + 4y = 216, we will use the method of Lagrange multipliers. Here’s how:

  1. Define the Lagrange Function:

    Given: f(x,y)=48x+96yx22xy9y2f(x, y) = 48x + 96y - x^2 - 2xy - 9y^2 Constraint: g(x,y)=20x+4y216=0g(x, y) = 20x + 4y - 216 = 0

    We introduce a Lagrange multiplier λ\lambda and form the Lagrange function L(x,y,λ)\mathcal{L}(x, y, \lambda): L(x,y,λ)=f(x,y)+λ(21620x4y)\mathcal{L}(x, y, \lambda) = f(x, y) + \lambda (216 - 20x - 4y)

  2. Compute Partial Derivatives:

    We need to set the partial derivatives of L\mathcal{L} with respect to xx, yy, and λ\lambda equal to zero.

    Partial derivative with respect to xx: Lx=482x2y20λ=0\frac{\partial \mathcal{L}}{\partial x} = 48 - 2x - 2y - 20\lambda = 0

    Partial derivative with respect to yy: Ly=962x18y4λ=0\frac{\partial \mathcal{L}}{\partial y} = 96 - 2x - 18y - 4\lambda = 0

    Partial derivative with respect to λ\lambda: Lλ=21620x4y=0\frac{\partial \mathcal{L}}{\partial \lambda} = 216 - 20x - 4y = 0

  3. Solve the System of Equations:

    We now have three equations: 482x2y20λ=048 - 2x - 2y - 20\lambda = 0 962x18y4λ=096 - 2x - 18y - 4\lambda = 0 21620x4y=0216 - 20x - 4y = 0

    Solving this system will give us the values of xx, yy, and λ\lambda that minimize f(x,y)f(x, y) subject to the constraint.

Let's proceed by solving these equations step-by-step.The solution to the system is: x=10,y=4,λ=1x = 10, \quad y = 4, \quad \lambda = 1

Thus, the values of x=10x = 10 and y=4y = 4 minimize the function f(x,y)f(x, y) subject to the constraint 20x+4y=21620x + 4y = 216.

Would you like a detailed step-by-step explanation, or do you have any questions about this solution?

Here are five questions to expand your understanding:

  1. How does the method of Lagrange multipliers work in optimization problems?
  2. Why is it important to set partial derivatives to zero in this method?
  3. What would change if the constraint equation had a different form, such as a nonlinear equation?
  4. How would the approach differ if we were maximizing f(x,y)f(x, y) instead of minimizing?
  5. Can Lagrange multipliers be used for functions with more than two variables or constraints?

Tip: When solving optimization problems with constraints, always check that the solutions satisfy both the constraint and any boundaries of the problem's domain if they exist.

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Math Problem Analysis

Mathematical Concepts

Optimization
Lagrange Multipliers
Multivariable Calculus
Constrained Optimization

Formulas

Lagrange Function: L(x, y, λ) = f(x, y) + λ * (g(x, y))
Partial Derivatives of Lagrange Function: ∂L/∂x = 0, ∂L/∂y = 0, ∂L/∂λ = 0

Theorems

Lagrange Multiplier Theorem

Suitable Grade Level

Undergraduate (Calculus I & II)