Math Problem Statement

A series of questions involving physics problems such as determining acceleration, displacement, velocity, and distance using basic kinematics and graphical methods.

Solution

Let's go through the questions one by one and provide detailed solutions:

1. Determining the acceleration of a car:

  • Initial velocity (uu) = 20.5 m/s
  • Final velocity (vv) = 50.1 m/s
  • Time (tt) = 3.47 s

The formula for acceleration (aa) is: a=vuta = \frac{v - u}{t} a=50.1m/s20.5m/s3.47sa = \frac{50.1 \, \text{m/s} - 20.5 \, \text{m/s}}{3.47 \, \text{s}}

Calculate this value for the acceleration. Then, to find the distance traveled (ss), use: s=ut+12at2s = ut + \frac{1}{2}at^2

2. Finding the car's average acceleration:

  • Final velocity = 70 km/h (convert to m/s: 70×10003600=19.4470 \times \frac{1000}{3600} = 19.44 m/s)
  • Initial velocity = 0 m/s
  • Time = 7 seconds

Use the same formula as before: a=vuta = \frac{v - u}{t}

3. Finding the pitch speed:

  • Distance = 85 m
  • Time = 4 seconds

The formula for speed (vv) is: v=dtv = \frac{d}{t}

4. Calculating bullet travel time:

  • Speed = 850 m/s
  • Distance = 1 km (1000 m)

Time=DistanceSpeed\text{Time} = \frac{\text{Distance}}{\text{Speed}}

5. Derrick’s distance and displacement:

  • Walks 4 feet, then turns 90 degrees and crawls 6 feet.

For distance, sum up the total movement. For displacement, use the Pythagorean theorem to find the straight-line distance.

6. Sir Jan's distance and displacement:

He walks 2 meters to the park and returns.

  • Distance = 2 + 2 = 4 meters.
  • Displacement = 0 meters (since he returns to the start).

7. Resultant displacement:

  • Vector A: 2.3 km at 45° South of West
  • Vector B: 4.8 km North

Use vector addition to determine the resultant displacement. Decompose each vector into components and sum them.

8. Graphical vector addition:

  • Vectors: A = 7 m (E), B = 8 m (30° S of W), C = 3 m (NE).

Use the head-to-tail method to add these vectors graphically. Determine the magnitude and direction of the resultant vector.

9. Bike ride graph:

  • Analyze the graph for each question:
    • a. Duration of stationary time.
    • b. Total distance.
    • c. Average speed over the specified time interval.

10. Sprinter's velocity-time graph:

  • a. Acceleration between 0 and 20 seconds (calculate the slope of the velocity graph).
  • b. Speed at 8 seconds (check the graph value).
  • c. Constant speed interval (where the graph is horizontal).

Would you like the solutions worked out in detail for each of these problems?

Related Questions:

  1. What is the significance of using vector components when finding the resultant vector?
  2. How does the conversion from km/h to m/s affect the calculation of acceleration?
  3. Why is displacement sometimes zero even when distance is not?
  4. How can you determine whether a force is acting on an object from a velocity-time graph?
  5. What does the slope of a distance-time graph represent?

Tip:

Always convert units to the standard (e.g., m/s for velocity) before performing calculations to ensure consistency and accuracy.

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Math Problem Analysis

Mathematical Concepts

Kinematics
Vector addition
Graphical analysis
Distance-time graphs
Velocity-time graphs

Formulas

Acceleration: a = (v - u) / t
Distance: s = ut + 1/2at^2
Speed: v = d / t
Time: t = d / v
Displacement using Pythagorean theorem: d^2 = x^2 + y^2

Theorems

Pythagorean theorem
Basic principles of kinematics

Suitable Grade Level

Grades 10-12