Choose the correct terms to complete the sentences.

Consider Kepler’s third law. If the orbital period of a celestial body is 27 days and its 
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 axis, or the widest part of its orbit, is 0.3844 x 106 km, then the mass of the 
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 object is 
Choose...
 x 1024 kg.

To complete the sentences with the correct terms based on Kepler's third law:

"Consider Kepler’s third law. If the orbital period of a celestial body is 27 days and its **semi-major axis**, or the widest part of its orbit, is 0.3844 x 10⁶ km, then the mass of the **central** object is **5.97** x 10²⁴ kg."

Explanation:
- The **semi-major axis** is the correct term for the "widest part" of an orbit.
- The **central** object is the one whose mass affects the orbiting body's motion (e.g., the Earth for the Moon).
- The mass of the central object, Earth, is approximately 5.97 x 10²⁴ kg.

Would you like more details on how Kepler's third law relates orbital periods to the masses of celestial objects? Here are some follow-up questions:

1. How does Kepler's third law apply to planetary motion?
2. What is the significance of the semi-major axis in an elliptical orbit?
3. How do scientists use Kepler's laws to calculate the mass of stars or planets?
4. Why is the orbital period important in determining the characteristics of a celestial body?
5. How does changing the mass of the central object affect the orbital period?

**Tip:** In an elliptical orbit, the semi-major axis is crucial because it represents the average distance between the celestial body and the central object over one full orbit.

Consider Kepler’s third law. If the orbital period of a celestial body is 27 days and its axis, or the widest part of its orbit, is 0.3844 x 10⁶ km, then the mass of the object is x 10²⁴ kg.

Learn how to use Kepler's Third Law to calculate the mass of a central object, given an orbital period of 27 days and a semi-major axis of 0.3844 x 10⁶ km. This problem covers key celestial mechanics concepts and is suitable for high school students.

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