Math Problem Statement

Suppose that z varies jointly with the cube of x and the square of y. Find the constant of proportionality k if z = 601.6 when y = 4 and x = 2. Using the k from above, write the variation equation in terms of x and y. Using the k from above, find z given that y = 14 and x = 7.

Solution

To solve for zz when y=14y = 14 and x=7x = 7, given the variation equation:

z=4.7x3y2z = 4.7 \cdot x^3 \cdot y^2

we can substitute the values of xx and yy into the equation as follows:

  1. Substitute x=7x = 7 and y=14y = 14 into the equation:

    z=4.7(7)3(14)2z = 4.7 \cdot (7)^3 \cdot (14)^2

  2. Calculate each component step-by-step:

    • 73=3437^3 = 343
    • 142=19614^2 = 196
  3. Substitute these values back:

    z=4.7343196z = 4.7 \cdot 343 \cdot 196

  4. Multiply the values:

    z=4.767228z = 4.7 \cdot 67228

  5. Finally, multiply by 4.74.7:

    z=316971.6z = 316971.6

Therefore, the answer is:

z=316971.6z = 316971.6

Would you like further details on any part of this calculation?

Related Questions:

  1. How does joint variation differ from direct variation?
  2. How do you derive the constant of proportionality?
  3. What are some examples of real-world applications of joint variation?
  4. How would the equation change if zz varied with the fourth power of xx?
  5. What steps would you take if asked to find xx or yy instead of zz?

Tip: Always double-check your substitutions and calculations, especially when dealing with exponents, as small errors can lead to large discrepancies in answers.

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Math Problem Analysis

Mathematical Concepts

Joint Variation
Exponentiation

Formulas

z = k * x^3 * y^2

Theorems

Joint Variation Theorem

Suitable Grade Level

Grades 9-12