Math Problem Statement

Find an equation of variation where y varies jointly as x and the square of​ z, and wherenbsp y equals 66 when xequals15 and zequals2.

Solution

To solve this problem, we use the formula for joint variation.

When yy varies jointly as xx and the square of zz, the relationship can be written as:

y=kxz2y = k \cdot x \cdot z^2

Where:

  • kk is the constant of proportionality,
  • xx is one variable,
  • zz is another variable, and
  • yy is the dependent variable.

Step 1: Write the equation with the given values.

Given:

  • y=66y = 66,
  • x=15x = 15,
  • z=2z = 2.

Substitute these values into the equation:

66=k15(2)266 = k \cdot 15 \cdot (2)^2

66=k15466 = k \cdot 15 \cdot 4

66=k6066 = k \cdot 60

Step 2: Solve for kk.

To find kk, divide both sides by 60:

k=6660=1.1k = \frac{66}{60} = 1.1

Step 3: Write the final equation.

Now that we know k=1.1k = 1.1, substitute it back into the original equation:

y=1.1xz2y = 1.1 \cdot x \cdot z^2

This is the equation of variation where yy varies jointly as xx and the square of zz.


Do you have any questions or would you like further details?

Here are 5 related questions:

  1. What is joint variation, and how does it differ from direct variation?
  2. Can you derive the formula for inverse variation?
  3. How would the equation change if yy varied inversely as xx?
  4. What would happen if zz were squared, but xx remained unaffected?
  5. How can you calculate the constant of proportionality in different contexts?

Tip: In joint variation, keep an eye on how multiple variables influence each other to maintain their proportional relationships.

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Math Problem Analysis

Mathematical Concepts

Joint Variation
Algebra

Formulas

y = k * x * z^2

Theorems

Joint Variation Theorem

Suitable Grade Level

Grades 9-12