Math Problem Statement
Solution
Let's outline Jan's motion based on the description:
- Jan starts at 5 meters from a motion sensor and walks 4 meters toward it over a period of 5 seconds.
- She then walks 2 meters away from the motion sensor over the next 3 seconds.
- Jan stops and waits for 2 seconds.
Here's how to draw the distance versus time graph for Jan's motion:
- Start at 5 meters at seconds.
- At seconds, Jan walks 4 meters towards the sensor, reaching meter from the sensor.
- From to seconds, she walks 2 meters away from the sensor, moving to meters from the sensor.
- From to seconds, Jan remains stationary at 3 meters from the sensor.
The graph should look like a piecewise linear plot:
- Decrease from 5 meters to 1 meter in the first 5 seconds (slope: -0.8 meters/second).
- Increase from 1 meter to 3 meters between 5 and 8 seconds (slope: +0.67 meters/second).
- Remain flat at 3 meters from 8 to 10 seconds.
Would you like to see a visual representation of this graph? Here are some further questions and tips related to the concept:
- What does the slope of each segment on a distance-time graph represent?
- How would the graph change if Jan walked faster or slower during each segment?
- What is the significance of the slope changing signs on a distance-time graph?
- How can we determine Jan's average speed during her walk?
- What would the graph look like if Jan decided to walk in a continuous loop rather than stopping?
Tip: When analyzing motion on a distance-time graph, note that a steeper slope indicates faster motion, while a flat line indicates no motion.
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Math Problem Analysis
Mathematical Concepts
Kinematics
Distance-Time Graph
Rates of Change
Formulas
Distance = Speed × Time
Slope = Δy/Δx (Rate of Change)
Theorems
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Suitable Grade Level
Grade 8-10
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