To isolate \( \frac{1}{R_{eq}} \) in the equation

\[
\frac{1}{R_{eq}} = \frac{1}{r_1} + \frac{1}{r_2},
\]

no additional steps are necessary because \( \frac{1}{R_{eq}} \) is already isolated. The equation shows that \( \frac{1}{R_{eq}} \) is equal to the sum of \( \frac{1}{r_1} \) and \( \frac{1}{r_2} \).

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Here are 5 related questions to consider:
1. How can you find \( R_{eq} \) from the equation \( \frac{1}{R_{eq}} = \frac{1}{r_1} + \frac{1}{r_2} \)?
2. What happens to \( R_{eq} \) if \( r_1 \) and \( r_2 \) are equal?
3. How does the equivalent resistance \( R_{eq} \) change if another resistor \( r_3 \) is added in parallel?
4. Can this formula be extended to more than two resistors? How?
5. How would you approach solving \( R_{eq} \) if \( r_1 \) and \( r_2 \) are given in different units?

**Tip:** Remember that in parallel circuits, the equivalent resistance is always less than the smallest individual resistance.

Understand how to isolate 1/Req in the equation 1/Req = 1/r1 + 1/r2 for parallel electrical circuits. This detailed explanation covers the concept of equivalent resistance, suitable for high school students studying electrical circuits.

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