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To determine if the ordered pair \((4,3)\) is a solution to the equation \(2x + 5y = 26\), we can substitute \(x = 4\) and \(y = 3\) into the equation and check if both sides are equal.

Given equation:
\[
2x + 5y = 26
\]

Substitute \(x = 4\) and \(y = 3\):
\[
2(4) + 5(3) = 26
\]
\[
8 + 15 = 26
\]
\[
23 \neq 26
\]

Since \(23\) does not equal \(26\), the ordered pair \((4,3)\) is **not** a solution to the equation.

### Final Answer:
\((4,3)\) is not a solution.

Would you like more details, or do you have any questions?

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### Related Questions
1. What steps can you take to verify if any ordered pair is a solution to an equation?
2. How can you determine if an equation has multiple solutions or only one?
3. What does it mean for an ordered pair to be a solution to a system of equations?
4. How do you solve for \(y\) in terms of \(x\) for the equation \(2x + 5y = 26\)?
5. What is the graphical interpretation of a solution to a linear equation?

### Tip
When testing an ordered pair in an equation, always substitute both values and simplify each side to check for equality.

Determine whether the ordered pair (4,3) is a solution to the equation 2x+5y=26.

Check if the ordered pair (4,3) is a solution to the linear equation 2x + 5y = 26 by using substitution. This solution involves substituting x = 4 and y = 3 and verifying the equation's equality, suitable for students in Grades 7-8.

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